Answer:
Boiling point: physical
Density: physical
Ductility: physical
Heat of combustion: chemical
Explanation:
Chemical properties can only be analyzed by putting the substance through a chemical reaction, such as combustion.
Physical properties can be analyzed without altering the substance chemically. With that in mind:
0.01 m
< 0.03 m
< 0.04 m urea
As molal concentration rises, so does freezing point depression. It can be expressed mathematically as ΔTf = Kfm.
<h3>What is Colligative Properties ?</h3>
- The concentration of solute particles in a solution, not the composition of the solute, determines a colligative properties .
- Osmotic pressure, boiling point elevation, freezing point depression, and vapor pressure reduction are examples of ligand-like properties.
<h3>What is freezing point depression?</h3>
- When less of another non-volatile material is added, the temperature at which a substance freezes decreases, a process known as Freezing-point depression.
- Examples include combining two solids together, such as contaminants in a finely powdered medicine, salt in water, alcohol in water.
- An significant factor in workplace safety is freezing points.
- If a substance is kept below its freezing point, it may become more or less dangerous.
- The freezing point additionally offers a crucial safety standard for evaluating the impacts of worker exposure to cold conditions.
Learn moree about Colligative Properties here:
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<span>M<span><span>g<span>(s)</span></span>+</span>2HC<span>l<span>(aq)</span></span>→MgC<span>l<span>2<span>(aq)</span></span></span>+<span>H<span>2<span>(g)</span></span></span></span>
Explanation:
The reaction between magnesium and hydrochloric
acid combine to form a salt of magnesium chloride and release hydrogen
gas. This single replacement reaction is a classic example of a metal
reacting in an acid to release hydrogen gas.
Answer is: <span>A. 18.02 g/mol.
At standard temperature and pressure 1 mol of gas occupied 22.4 liters:
V(H</span>₂O) = 22.4 L; volume of water.
Vm = 22.4 L/mol; molar volume at STP.
n(H₂O) = V ÷ Vm.
n(H₂O) = 22.4 L ÷ 22.4 L/mol.
n(H₂O) = 1 mol; amount of substance (water).
M(H₂O) = Ar(O) + 2Ar(H) · g/mol.
M(H₂O) = 16 + 2 ·1.01 · g/mol.
M(H₂O) = 18.02 g/mol; molar mass of water.
Answer:
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Explanation:
The balanced chemical reaction to obtain water from SnO₂ is:
The mole ratio is:

Find the number of moles equivalent to 1.20× 10²¹ molecules of water, using Avogadro's number:

From the mole ratio, the number of moles of SnO₂ are half the number of moles of water. That is:
- 0.0019927 moles / 2 = 0.00099635 moles of SnO₂
Use the molar mass of SnO₂ to convert the number of moles to grams:
- molar mass of SnO₂ = 150.71g/mol
- mass of SnO₂ = 0.00099635mol × 150.71 g/mol = 0.150 grams.
The answer must be reported with 3 significant figures.