1 kg/L -------------- 0.001 kg/mL
22.4 kg/L --------- ??
22.4 x 0.001 / 1 => 0.0224 kg/mL
The amount, in grams, of that would be produced from the burning of 3.0 mol amyl alcohol would be 660.15 grams
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
The mole ratio of amyl alcohol to the produced is 2:10.
Thus, for 3.0 mol of amyl alcohol, 15 mol of would be produced.
Mass of 15 mol = 15 x 44.01 = 660.15 grams
More on stoichiometric calculations can be found here: brainly.com/question/8062886
A) Adding Cream And Milk To The Mixture. Hope This Helps :)
1GeF3 + 3Cs = 3Csf +1Ge
DONT HATE ME IF ITS WRONG PLS
Answer:
The effect is the increasing of the molar concentration.
Explanation:
When you standarize a solution of NaOH with KHP you are establish its molar concentration (That is the amount of moles of NaOH per liter of solution).
If you evaporated some water of the solution, you are increasing its concentration because volume is decreasing doing the amount of moles per liter increasing.