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nikitadnepr [17]
2 years ago
14

I run the reaction below using 55.0 g sodium chloride and plenty of fluorine, and it produces 8.8 grams of chlorine gas. What is

its percent yield?
Chemistry
1 answer:
Oxana [17]2 years ago
5 0

Answer:

The answer is below!!

Explanation:

Moles of Na=44.0g Na ×1 mol Na22.99g Na =1.914 mol Na.

Moles of Cl2=69.9g Cl2 ×1 mol Cl270.91g Cl2 =0.9858 mol Cl2.

Theoretical yield=1.914mol Na ×2 mol NaCl2mol Na =1.914 mol NaCl.

When reacting Na with Cl2, we calculated that the theoretical yield should be 12.5 grams. Our actual yield was 13.0 grams. What is the percent yield? 24 grams of CH4 were added to the above reaction.

Hope I Helped!!

:)

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A chemist dissolves 614. mg of pure hydrochloric acid in enough water to make up 400 mL of solution. Calculate the pH of the sol
tatuchka [14]

Answer:

The pH of the solution is 1.38.

Explanation:

Mass of HCl = 614 mg = 0.614 g

Moles of HCl = \frac{0.614 g}{36.5 g/ mol}=0.01682 mol

Concentration of HCl :

Concentration =\frac{Moles}{\text{Volume of solution in L}}

On adding 0.01682 moles to 400 mL of water that 0.4 L of water.

[HCl]=\frac{0.01682 mol}{0.4 L}=0.04205 M

HCl(s)+H_2O(l)\rightarrow H_3O^+(aq)+Cl^-(aq)

1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.

Then 0.04205 mol/L of HCl will give:

1\times 0.04205 M =0.04205 mol/L of hydronium ions.

[H_3O^+]=0.04205 M

pH=-\log [H_3O^+]

pH=-\log [0.04205 M]=1.38

The pH of the solution is 1.38.

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Third, cis means that the two Br are placed in opposed positions, this is drawn with one Br up and the other down. So, you need to represent the position of the Br in the space:


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