Question

I run the reaction below using 55.0 g sodium chloride and plenty of fluorine, and it produces 8.8 grams of chlorine gas. What is its percent yield?

Answer 1

Answer:

The answer is below!!

Explanation:

Moles of Na=44.0g Na ×1 mol Na22.99g Na =1.914 mol Na.

Moles of Cl2=69.9g Cl2 ×1 mol Cl270.91g Cl2 =0.9858 mol Cl2.

Theoretical yield=1.914mol Na ×2 mol NaCl2mol Na =1.914 mol NaCl.

When reacting Na with Cl2, we calculated that the theoretical yield should be 12.5 grams. Our actual yield was 13.0 grams. What is the percent yield? 24 grams of CH4 were added to the above reaction.

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