No, simple machine will have an efficiency of 100% if he output work of the machine is equal to the work input.
Given v_in = 20 m/s and a = 3 m/s2, assuming that the body
moves at constant acceleration, the motion is modeled by the equation:
s(t) = (v_in)t + (1/2)a(t^2)
where s(t) is the distance traveled
substituting the given,
s(t) = 20t + (3/2)(t^2)
at t = 3
s(t) = 20(3) + (3/2)(3)^2
= 73.5 m
It states that energy neither be created nor be destroyed.energy may only be transform from one form to another. example mechanical energy= ek + ep
The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 * m/s
Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.
By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.
given
charge of electron = 1.6 × C
mass of electron = 9.1 × kg
Force in an electric field = q*E
potential energy is stored in the form of work done
potential energy = work done = Force * displacement
= q * (E * d)
= q * (V) = 1.6 × * 100
stored potential energy = kinetic energy in electric field
kinetic energy = 1/2 * m *
= 1/2 * 9.1 × *
equation both the equations
1/2 * 9.1 × * = 1.6 ×
= 0.352 * m/s
= 35.2 *
= 5.93 * m/s
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The ball's initial velocity must be 28.0 m/s
Explanation:
The motion of the ball in this problem is a projectile motion, so it follows a parabolic path, consisting of two separate motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
First, we study the vertical motion of the ball: since it is a uniformly accelerated motion, we can use the suvat equation to find the time it takes for the ball to reach the ground,
where
s = 40 m is the vertical displacement, the height of the cliff (we chose downward as positive direction)
u = 0 is the initial vertical velocity of the ball
t is the time of flight of the ball
is the acceleration of gravity
Solving for t, we find:
Now we can analyze the horizontal motion: since this is a uniform motion, the horizontal speed is constant, and it is given by
where:
d = 80 m is the horizontal distance covered by the ball
t = 2.86 s is the time of flight
Substituting,
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