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MArishka [77]
2 years ago
12

What is the molarity of a solution formed when you add 200. Ml of water to 50. Ml of 5. 0 m hcl

Chemistry
1 answer:
Gnesinka [82]2 years ago
6 0

The molarity of a solution formed when you add 200 mL of water to 50 mL of 5. 0 M HCl is 1.25M.

<h3>How to calculate molarity?</h3>

The molarity of a solution can be calculated using the following formula:

M1V1 = M2V2

Where;

  • M1 = molarity of a base
  • M2 = molarity of acid
  • V1 = volume of base
  • V2 = volume of acid

M1 × 200 = 50 × 5

200M1 = 250

M1 = 250/200

M1 = 1.25M

Therefore, the molarity of a solution formed when you add 200 mL of water to 50 mL of 5. 0 M HCl is 1.25M.

Learn more about molarity at: brainly.com/question/12127540

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The air inside a flexible 3.5L container has a pressure of 115Kpa. What should the volume of the container be increased to in th
LenaWriter [7]

Answer:

V₂ = 4.82 L

Explanation:

Given data:

Initial volume of gas = 3.5 L

Initial pressure = 115 Kpa

Final volume = ?

Final Pressure = 625 torr

Solution:

Final Pressure = 625 torr (625/760 =0.82 atm)

Initial pressure = 115 Kpa (115/101 = 1.13 atm)

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.13 atm × 3.5 L = 0.82 atm × V₂

V₂ = 3.955 atm. L/0.82 atm

V₂ = 4.82 L

5 0
4 years ago
What was the name of the start of something new in science?
AURORKA [14]
I googled it and all it came up for is the Wikipedia for high school musical.
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6 0
3 years ago
A 1.50 g sample of solid NH₄NO₃ was added to 35.0 mL of water in a styrofoam cup (insulated from the environment) and stirred un
GaryK [48]

Answer : The heat of the reaction is, 1.27 kJ/mole

Explanation :

First we have to calculate the heat released.

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat = ?

m = mass of sample = 1.50 g

c = specific heat of water = 4.81J/g^oC

T_1 = initial temperature  = 22.7^oC

T_2 = final temperature  = 19.4^oC

Now put all the given value in the above formula, we get:

Q=1.50g\times 4.81J/g^oC\times (19.4-22.7)^oC

Q=-23.8095J=-0.0238kJ

Now we have to calculate the heat of the reaction in kJ/mol.

\Delta H=\frac{Q}{n}

where,

\Delta H = enthalpy change = ?

Q = heat released = 0.0238 kJ

n = number of moles NH₄NO₃ = \frac{\text{Mass of }NH_4NO_3}{\text{Molar mass of }NH_4NO_3}=\frac{1.50g}{80g/mol}=0.01875mole

\Delta H=\frac{0.0238kJ}{0.01875mole}=1.27kJ/mole

Therefore, the heat of the reaction is, 1.27 kJ/mole

8 0
3 years ago
If we have equal masses of copper at 80oC and water at 20oC and we put them together, what is the final temperature?
Ket [755]

Answer:

The final temperature will be close to 20°C

Explanation:

First of all, the resulting temperature of the mix can't be higher than the hot substance's (80°C) or lower than the cold one's (20°C). So options d) and e) are imposible.

Now, due to the high heat capacity of water (4,1813 J/mol*K) it can absorb a huge amount of heat without having a great increment in its temperature. On the other hand, copper have a small heat capacity (0,385 J/mol*K)in comparison.

In conclusion, the copper will release its heat decreasing importantly its temperature and the water will absorb that heat resulting in a small increment of temperature. So the final temperature will be close to 20°C

<u>This analysis can be done because we have equal masses of both substances. </u>

6 0
4 years ago
A. Monosaccharide with examples
san4es73 [151]
Monosaccharide are
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examples: fructose ,galactose glucose
7 0
3 years ago
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