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3 years ago

How do you know how many valence electrons are in a molecule?

Chemistry

2 answers:

telo118 [61]3 years ago

4 0

1. by making a atomic configuration
2.by making a table of shells of k.l.m.n....
that's all

Leno4ka [110]3 years ago

4 0

To know the number of valence electrons you must know the number of electrons in the outer shell .. In the periodic table there are 8 groups (which are the vertical columns) .. ignore the yellow ones for now which are the transition metals .. the group number is the number of electrons in the most outer shell of an atom .. so for example lithium and sodium are in group 1 so they have only 1 electron in their outer shell .. the valence electrons are the ones an atom looses or gains during a chemical reaction (atoms try to be stable by having 8 electrons in their outer most shell) .. for example atoms in group 1 have 1 electron in their outer shell that they want to loose so the valency is 1 .. In group 5 they need to become 8 so they gain 3 electrons so the valency is 3

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As you move from left to right across a period, what happens to the atomic radil?

egoroff_w [7]

Answer:

Moving Across a Period

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3 years ago

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Mazyrski [523]

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3 years ago

A syringe initially holds a sample of gas with a volume of 285 mL at 355 K and 1.88 atm. To what temperature must the gas in the

Ivahew [28]

<u>Answer:</u> The temperature to which the gas in the syringe must be heated is 720.5 K

<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=1.88atm\\V_1=285mL\\T_1=355K\\P_2=2.50atm\\V_2=435mL\\T_2=?K$

Putting values in above equation, we get:

$\frac{1.88atm\times 285mL}{355K}=\frac{2.50atm\times 435mL}{T_2}\\\\T_2=\frac{2.50\times 435\times 355}{1.88\times 285}=720.5K$

Hence, the temperature to which the gas in the syringe must be heated is 720.5 K

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3 years ago

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liraira [26]

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To know more about line segment visit :

brainly.com/question/25727583

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1 year ago

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dedylja [7]

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