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swat32
3 years ago
7

Normally the capital ÎGo° for a reaction would be determined at standard temperature with each reactant at a concentration of 1

M. Letâs assume that the 1 M 2-PG solution will reach the same equilibrium ratio that would be observed under standard conditions. The enzyme enolase catalyzes the conversion of 2-PG to phosphoenolpyruvate (PEP) in living systems. You find that when you add enolase to your 2-PG solution it reaches an equilibrium with 0.68M PEP and 0.32 M 2-PG. What is the capital ÎGo° for this reaction?
Use R= 1.987 cal/mol.K

a. +559 cal/mol
b. - 559 cal/mol
c. +379 cal/mol
d.-379 cal/mol
Chemistry
1 answer:
Arte-miy333 [17]3 years ago
8 0

Answer:

d.-379 cal/mol

Explanation:

ΔG = ΔG⁰ + RT ln K

for equilibrium ΔG = 0

ΔG⁰ + RT ln K =0

ΔG⁰   =  -  RT ln K

PG ⇒ PEP

K = [ PEP ] / [ PG ]

= .68 / .32

= 2.125

ΔG⁰   =   - 1.987 x 273 x  ln 2.125

= - 409 Cal / mole

Option d is the nearest answer .

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 How much energy is needed to raise the temperature of 125g of water from 25.0oC to 35.0oC?  The specific heat of water is 4.184
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Hello!

To find the amount of energy need to raise the temperature of 125 grams of water from 25.0° C to 35.0° C, we will need to use the formula: q = mcΔt.

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Firstly, we can find the change in temperature. We are given the initial temperature, which is 25.0° C and the final temperature, which is 35.0° C. It is found by subtract the final temperature from the initial temperature.

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3 years ago
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2 years ago
Read 2 more answers
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