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RoseWind [281]
2 years ago
9

What potential difference is required across an 32 -Ω resistor to cause 33.72 A to flow through it?​

Physics
1 answer:
Inessa05 [86]2 years ago
6 0

\text{Voltage,}~ V = IR =33.72\times 32 =  1079.04~ \text{volt}

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The discharge of a stream is Choose one: likely to decrease downstream in arid regions and increase downstream in temperate regi
Sauron [17]

Answer:

<em>likely to decrease downstream in arid regions and increase downstream in temperate regions</em>

<em></em>

Explanation:

Arid regions are is a region with a severe lack of water, usually to the extent that affect the organisms living in the region. Arid regions are characterized by a very low depth of rainfall per year. Temperate region on the other hand experience more distinct seasonal change and wider temperature change. Temperate regions get a fairly large amount of rainfall per year.

In arid regions, the soil is very dry, and the rate of infiltration and percolation is high relative to the amount of rainfall available. The effect is that more water is infiltrated into the soil as you move downstream, leading to a decrease in the discharge of a stream as you move downstream. Most temperate region have soils that are usually saturated in the peak of the rainfall season, leading to a greater stream discharge as you move downstream.  

3 0
3 years ago
A speed-time graph is shown below:
VladimirAG [237]

Answer: 0.5 m/s^{2}

Explanation:

Average acceleration a_{ave} is the variation of velocity \Delta V over a specified period of time \Delta t:

a_{ave}=\frac{\Delta V}{\Delta t}}

Where:

\Delta V=V_{f}-V_{o} being V_{o}=0 cm/s the initial velocity and V_{f}=4 cm/s the final velocity  (according to the information given from the described graph)

\Delta t=8 s

Then:

a_{ave}=\frac{4 cm/s -0 cm/s}{8 s}}

a_{ave}=0.5 m/s^{2}

5 0
3 years ago
A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar
notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2>\omega = 0.23 rad/s</h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

L_i = L_f

now we can say

m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega

so we will have

0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega

\omega = 0.23 rad/s

Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

6 0
3 years ago
4.0 kg objects mive a distance of 7.8 m under the action of a cinstant gorce of 5.6 N. how much work is dine on object?
alexdok [17]

Answer:

43.68 J

Explanation:

Distance moved= 7.8 m

Force = 5.6 N

Work Done= Distance moved * Force

                   = 7.8 *5.6

                      =43.68 Joules

6 0
3 years ago
_______ from the mantle rises and flows out through a vent onto Earth's surface as _______. This molten material, sometimes alon
anygoal [31]
Magma from the mantle rises and flows out through a vent onto Earth's surface as lava. This molten material, sometimes along with ash, cinders, and rock, builds up a mountain around the vent. The vent and its mountain together are called a sediment.


hope this helps
5 0
3 years ago
Read 2 more answers
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