Answer:
(1) Bromination, (2) E2 elimination and (3) epoxidation
Explanation:
- In the first step, -OH group in cyclopentanol is replaced by more facile leaving group Br by treating cyclopentanol with
- In the second step, E2 elimination in presence of strong base e.g. NaOEt/EtOH produce cyclopentene
- In the third step, treatment of cyclopentene with mCPBA produces 1,2-epoxycyclopentane
- Full reaction scheme has been shown below
Answer:
A
Explanation:
The answer would be A because Inertia is when a property of matter remains unchanged.
<span>B. S⁰(s) + 2H⁺ + 2e⁻ –--> H2S⁰(g)
by mass: 1 S and 2 H ----> 2 H and 1S True.
by charge : 0 +(2*(+1)) + 2*(-1) = 0, 0+2-2=0, 0 = 0 True.</span>
Answer:
They all have the same number of protons but different numbers of neutrons.
Explanation:
Elements will always have the same number of protons no matter the isotopes. Isotopes only change the number of neutrons. Silicon will always have 14 protons. So silicon-28 has 14 protons and 14 neutrons. Silicon-29 has 14 protons and 15 neutrons. Silicon-30 has 14 protons and 16 neutrons.
