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Harrizon [31]
2 years ago
13

the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on

the surface of its support.?​
Physics
2 answers:
aleksandr82 [10.1K]2 years ago
6 0

Answer:

your answer is here 180

Explanation:

900/2.5 * 2 = 180

daser333 [38]2 years ago
6 0

Answer:

The answer is 180 Pa.

Explanation:

<h3><u>Given</u>;</h3>

Here, weight = thrust = 900 N,

dimensions are 2.5 m × 2 m × 1.2 m

<h3><u>To </u><u>Find</u>;</h3>
  • Pressure exerted by the block on the surface of its support.
<h3><u>Formula</u>;</h3>
  • Pressure = Thrust ÷ Area

We know that, Pressure is inversely proportional to area. For the minimum pressure the area must be more.

So, if the block is resting with 2.5 m × 2 m surface on the support, the pressure will be minimum.

Pressure = 900 N ÷ 2.5 × 2.0 m² = 180 Pa

Thus, The pressure exerted by the block on the support is 180 Pa.

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Explanation:

The density of an object can be calculated as

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Learn more about density:

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