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Harrizon [31]
2 years ago
13

the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on

the surface of its support.?​
Physics
2 answers:
aleksandr82 [10.1K]2 years ago
6 0

Answer:

your answer is here 180

Explanation:

900/2.5 * 2 = 180

daser333 [38]2 years ago
6 0

Answer:

The answer is 180 Pa.

Explanation:

<h3><u>Given</u>;</h3>

Here, weight = thrust = 900 N,

dimensions are 2.5 m × 2 m × 1.2 m

<h3><u>To </u><u>Find</u>;</h3>
  • Pressure exerted by the block on the surface of its support.
<h3><u>Formula</u>;</h3>
  • Pressure = Thrust ÷ Area

We know that, Pressure is inversely proportional to area. For the minimum pressure the area must be more.

So, if the block is resting with 2.5 m × 2 m surface on the support, the pressure will be minimum.

Pressure = 900 N ÷ 2.5 × 2.0 m² = 180 Pa

Thus, The pressure exerted by the block on the support is 180 Pa.

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shtirl [24]

Answer:

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3 0
3 years ago
What is the resistance of a carbon rod at 25.8 ∘C if its resistance is 0.0200 Ω at 0.0 ∘C ?
torisob [31]

0.02020 ohm is the resistance of a carbon rod at 25.8 ∘C if its resistance is 0.0200 Ω at 0.0 ∘C.

<h3 /><h3>What is a resistor?</h3>

A resistor is an electrical component that controls or restricts how much electrical current can pass across a circuit in an electronic device. A specified voltage can be supplied via resistors to an active device like a transistor.

The temperature of the resistor varies based on the variation in the temperature. The equation that describes the relationship between the two of them is:

R = R0[1+ alpha(T-T0)]  where:

R is the new resistance we are looking for

alpha is the temperature coefficient of resistance. For carbon rod, alpha = ₋ 4.8 x 10^{-4}(1/°c)

T0 is the standard temperature =25.8°C

R0 is the resistance at T0 = 0.0200 ohms

T is the temperature at which we want to get R = 0

Substitute in the equation to get R as follows:

R = 0.0200 [1+( ₋ 4.8 x 10^{-4}) (0-25.8)] = 0.02020 ohm

To know more about resistance refer to: brainly.com/question/11431009

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4 0
2 years ago
Calculate the maximum capillary rise/fall of mercury in a 0.5 mm radius glass capillary. Assume that the surface tension for mer
tekilochka [14]

Answer: 0.01 m

Explanation: The formulae for capillarity rise or fall is given below as

h = (2T×cosθ)/rpg

Where θ = angle mercury made with glass = 50°

T = surface tension = 0.51 N/m

g = acceleration due gravity = 9.8 m/s²

r = radius of tube = 0.5mm = 0.0005m

p = density of mercury.

h = height of rise or fall

From the question, specific gravity of density = 13.3

Where specific gravity = density of mercury/ density of water, where density of water = 1000 kg/m³

Hence density of mercury = 13.3×1000 = 13,300 kg/m³.

By substituting parameters, we have that

h = 2×0.51×cos 50/0.0005×9.8×13,300

h = 0.6556/65.17

h = 0.01 m

8 0
3 years ago
To lift a load of 100 kg a distance of 1 m an effort of 25 kg must be applied over an inclined plane of length 4 m. What must be
andreyandreev [35.5K]
Work = force * distance.
We must produce twice as much energy as we are lifting the weight twice as high.
But we are not increasing the force so we must increase the length of the ramp ( distance ) instead.
The new length will be twice as great as the previous length.
So 8 metres is required. 


25 kg * 8 m = work = 100 kg * 2 m
7 0
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What happens to the iron in the coilgun if the electricity in the coil was turned on
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