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LUCKY_DIMON [66]
4 years ago
14

A gas has a volume of 50.0 cm3 at a temperature of -73°C. What volume would the gas occupy at a temperature of -123°C if the pre

ssure stays constant?
f 5.0 cm3

g 3.75 cm3

h 37.5 cm3

j 50.0 cm3
Chemistry
1 answer:
GaryK [48]4 years ago
7 0

Answer:

h. 37.5 cm³

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT. </em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n  is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have different values of V and T:

<em>(V₁T₂) = (V₂T₁).  </em>

V₁ = 50.0 cm³, T₁ = -73°C + 273 = 200 K,

V₂ = ??? cm³, ​T₂ = -123°C + 273 = 150 K.

∴ V₂ = (V₁T₂)/(T₁) = (50.0 cm³)(150 K)/(200 K) = 37.5 cm³.

  • <em>So, the right choice is: </em><em>h. 37.5 cm³.</em>
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The answer is "5.18 ".

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We will first determine the solution's pOH. The following can possible:

The concentration of Hydroxide ion [OH^{-}] = 1.5\times 10^{-9}\ M

pOH =?\\\\pOH = -\log [OH^{-}]\\\\pOH = -\log 1.5\times 10^{-9}\\\\pOH = 8.82\\\\

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