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Allisa [31]
2 years ago
12

A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 ki

lograms with a standard deviation of 0. 5 kilograms. The company wishes to test the hypothesis H0:μ=12 against H1:μ<12 using a random sample of n=4 specimens. Calculate the P-value if the observed statistic is x⎯⎯=11. 25. Suppose that the distribution of the sample mean is approximately normal. Round your final answer to five decimal places (e. G. 98. 76543). Enter your answer in accordance to the question statement
Engineering
1 answer:
svet-max [94.6K]2 years ago
7 0

Answer:

The p-value of the hypothsis 0.00135

Explanation:

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Sketch the velocity profile for laminar and turbulent flow.
Margarita [4]

Answer:

The laminar flow is generally given in high viscosity fluids such as honey or oil, it has the characteristic of flowing in an orderly manner, the walls of the tube have a zero speed while in the center it has a maximum speed.

turbulent flow is characterized by fluid velocity vectors presenting themselves in a disorderly manner and in all directions.

I attached the drawings for the velocity profile in laminar and turbulent flow.

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3 years ago
What’s Statistics<br> What are the 2 Source of error in data collection
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3 years ago
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Is it a problem that the stress intensity factor, K, from Irwin's near-tip approximation approaches infinity as you get close to
valina [46]

Answer:

No it is not a problem

Explanation:

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and The application of stress intensity factor k in respect to present fatigue crack tip is termed " linear elastic fracture mechanics "

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3 years ago
In fuel oil piping systems, all exterior above-grade fill piping shall be __________ when tanks are abandoned or removed.
castortr0y [4]

Answer:

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6 0
3 years ago
An automobile has a mass of 1200 kg. What is its kinetic energy, in ki, relative to the road when traveling at a velocity of 50
netineya [11]

Answer:

a)Ek=115759.26J

b)23.15kW

Explanation:

kinetic energy(Ek) is understood as that energy that has a body with mass when it travels with a certain speed, it is calculated by the following equation

Ek=0.5mv^{2}

for the first part

m=1200Kg

V=50km/h=13.89m/s

solving for Ek

Ek=0.5(1200)(13.89)^2

Ek=115759.26J

For the second part of the problem we calculate the kinetic energy, using the same formula, then in order to find the energy change we find the difference between the two, finally divide over time (15s) to find the power.

m=1200kg

V=100km/h=27.78m/s

Ek=0.5(1200)(27.78)^2=462963J\\

taking into account all of the above the following equation is inferred

ΔE=\frac{Ek2-EK1}{T}=\frac{462963-115759.26}{15}  =23146.916W=23.15kW

3 0
3 years ago
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