Answer:
Normal boiling point is the temperature at which a liquid boils at 1 atmosphere of pressure.
Explanation:
Answer:
2.5 mol/L
Explanation:
We'll begin by calculating the number of mole in 7 g of KOH. This can be obtained as follow:
Mass of KOH = 7 g
Molar mass of KOH = 39 + 16 + 1
= 56 g/mol
Mole of KOH =?
Mole = mass /molar mass
Mole of KOH = 7 / 56
Mole of KOH = 0.125 mole
Next, we shall convert 50 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
50 mL = 50 mL × 1 L / 1000 mL
50 mL = 0.05 L
Finally, we shall determine the molarity of the KOH solution. This can be obtained as follow:
Mole of KOH = 0.125 mole
Volume = 0.05 L
Molarity of KOH =?
Molarity = mole / Volume
Molarity of KOH = 0.125 / 0.05
Molarity of KOH = 2.5 mol/L
Thus, the molarity of the KOH solution is 2.5 mol/L
Answer:
198.8mL
Explanation:
Step 1:
Data obtained from the question:
Molarity of base (Mb) = 3.5M
Volume of base (Vb) =..?
Molarity of acid (Va) = 2.75M
Volume of acid (Va) = 253mL
Step 2:
The balanced equation for the reaction.
HF + LiOH —> LiF + H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Step 3:
Determination of the volume of the base, LiOH needed for the reaction.
The volume of the base needed for the reaction can be obtained as follow:
MaVa /MbVb = nA/nB
2.75 x 253 / 3.5 x Vb = 1
Cross multiply
3.5 x Vb = 2.75 x 253
Divide both side by 3.5
Vb = 2.75 x 253 / 3.5
Vb = 198.8mL
Therefore, the volume of the base needed for the reaction is 198.8mL
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