Answer:
d. 3.0
Explanation:
First we <u>calculate the pOH of the solution</u>, using the following formula:
Using the pOH we can <u>calculate the pH of the solution</u>, keeping in mind the relationship between pH and pOH:
The answer is option d.
Answer:
(a) 1.95 × 10⁴ g
(b) 1.95 × 10⁷ mg
(c) 1.95 × 10¹⁰ μg
Explanation:
A dog has a mass of 19.5 kg.
<em>(a) What is the dog's mass in grams?</em>
1 kilogram is equal to 10³ grams. The mass of the dog in grams is:
19.5 kg × (10³ g/1 kg) = 1.95 × 10⁴ g
<em>(b) What is the dog's mass in milligrams?</em>
1 gram is equal to 10³ milligrams. The mass of the dog in milligrams is:
1.95 × 10⁴ g × (10³ mg/1 g) = 1.95 × 10⁷ mg
<em>(c) What is the dog's mass in micrograms?</em>
1 gram is equal to 10⁶ micrograms. The mass of the dog in micrograms is:
1.95 × 10⁴ g × (10⁶ μg/1 g) = 1.95 × 10¹⁰ μg
Recall the ideal gas law,
<em>P V</em> = <em>n R T</em>
Find the amount of CO₂ in the sample, <em>n</em> :
<em>P</em> = 686 mm Hg ≈ 91,459 Pa
<em>V</em> = 6.34 L
<em>R</em> = 8.3145 J/(mol•°K)
<em>T</em> = 73 °C = 346.2 °K
→ <em>n</em> = <em>P V</em> / (<em>R</em> <em>T</em> ) ≈ 0.20147 mol
Now find the volume <em>V</em> of the sample when the temperature <em>T</em> is 35 °C = 308.2 °K :
<em>V</em> = <em>n R T</em> / <em>P</em> ≈ 5.6349 L ≈ 5.63 L