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kati45 [8]
3 years ago
10

HELP PLEASE !!!!!!! If a ball is accelerating down through the air with no horizontal motion, what must be true about the net fo

rces acting on the ball? The gravitational force is greater than the drag. The net force on the ball is zero. The drag is greater than the gravitational force. The net force on the ball is directed upward.
physics
Physics
1 answer:
Allisa [31]3 years ago
6 0

Answer:

A. The gravitational force is greater than the drag.

Explanation:

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A massless, hollow sphere of radius R is entirely filled with a fluid such that its density is p. This same hollow sphere is now
Vesnalui [34]

Answer:

a. 8p

Explanation:

We are given that

Radius of hollow sphere , R1=R

Density of hollow sphere=\rho

After compress

Radius of hollow sphere, R2=R/2

We have to find density of the compressed sphere.

We know that

Density=\frac{mass}{volume}

Mass=Density\times volume=Constant

Therefore,\rho_1 V_1=\rho_2V_2

Volume of sphere=\frac{4}{3}\pi r^3

Using the formula

\rho\times \frac{4}{3}\pi R^3=\rho_2\times \frac{4}{3}\pi (R/2)^3

\rho R^3=\rho_2\times \frac{R^3}{8}

\rho_2=8\rho

Hence, the density of  the compressed sphere=8\rho

Option a is correct.

7 0
3 years ago
In a $100$ meter track event, Alice runs at a constant speed and crosses the finish line $5$ seconds before Beatrice does. If it
Liono4ka [1.6K]

Answer:

10s

Explanation:

If it took Beatrice 25 seconds to complete the race

Distance = 100 meter

Beatrice speed = 100/25

                          = 4m/s

If Alice runs at a constant speed and crosses the finish line $5$ seconds, she must have completed the race in 20s (25 -5).

Her speed where constant

= 100/20

= 5 m/s

It would take Alice

= 50/5

= 10s

It would take Alice 10s to run $50$ meters.

5 0
3 years ago
Dos cargas Q1=2pc y Q2=4pc estan separadas por una distancia de 6cm ¿con que fuerza se atraen?
noname [10]

Here we can use coulomb's law to find the force between two charges

As per coulombs law

]tex]F = \frac{kq_1q_2}{r^2}[/tex]

here we have

k = 9 * 10^9

q_1 = 2pC

q_2 = 4pC

r = 6cm = 0.06 m

now by using the above equation we have

F = \frac{9*10^9 * 2*10^{-12} * 4*10^{-12}}{0.06^2}

F = 2 * 10^{-11} N

so here the force between two charges is of above magnitude and this will be repulsive force between them as both charges are of same sign.

3 0
3 years ago
A student in Denver (altitude = 1 mile = 1609 m above sea level) brings a physics book of mass 1.3 kg to the top of a ten story
Nesterboy [21]

Answer:

Explanation:

Potential energy is the energy of a body due to is virtue of rest.

Potential energy is given as mgh

g is a constant and it is 9.81m/s²

And also the mass of the body is given as 1.3kg

Now the height of the body is

He took a book to a storey building of height 26m

He still holds the book 151 cm (1.51m) above the house.

The house is on an altitude of 1609m from the sea level.

Total Ug with out the sea level is

Ug=mgh

Ug=1.3 × 9.81 ×(26+1.51)

Ug=350.84J

Then, the potential energy due to the sea level is given as

Ug=mgh

Where g = 1/6371 m/s²

Therefore

Ug=mgh

Ug=1.3 × 1/6371 ×1609

Ug=0.328J

Total energy = 0.328+350.84

Ug=351.17J

8 0
3 years ago
What is the relationship between frequency ad wavelenght
Law Incorporation [45]

Answer:

Frequency and wavelength are inversely proportional to each other. The wave with the greatest frequency has the shortest wavelength. Twice the frequency means one-half the wavelength. For this reason, the wavelength ratio is the inverse of the frequency ratio.

7 0
3 years ago
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