Answer:
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Explanation:
Answer:Given h(x)=4x-4h(x)=4x−4, solve for xx when h(x)=0h(x)=0.
Explanation:
vGiven h(x)=4x-4h(x)=4x−4, solve for xx when h(x)=0h(x)=0.Given h(x)=4x-4h(x)=4x−4, solve for xx when h(x)=0h(x)=0.Given h(x)=4x-4h(x)=4x−4, solve for xx when h(x)=0h(x)=0.
Answer:
t = 1456.8 sec
Explanation:
given data:
contant k = 2.60*10^{-6}
rate of crystallization is 0.0013 s-1
rate of transformation is given by
use specifies value to solve
it is ime required for 50% tranformation
Avrami equation is given by
n = 1.88
second degree of recrystalization may be determine by rearranging original avrami equation
for 90%completion
t = 1456.8 sec
Answer:
the pressure reading when connected a pressure gauge is 543.44 kPa
Explanation:
Given data
tank volume (V) = 400 L i.e 0.4 m³
temperature (T) = 25°C i.e. 25°C + 273 = 298 K
air mass (m) = 3 kg
atmospheric pressure = 98 kPa
To find out
pressure reading
Solution
we have find out pressure reading by gauge pressure
i.e. gauge pressure = absolute pressure - atmospheric pressure
first we find absolute pressure (p) by the ideal gas condition
i.e pV = mRT
p = mRT / V
p = ( 3 × 0.287 × 298 ) / 0.4
p = 641.44 kPa
so
gauge pressure = absolute pressure - atmospheric pressure
gauge pressure = 641.44 - 98
gauge pressure = 543.44 kPa
Answer: For tiny leaks in pipes, use a compound stick available at most hardware stores. Simply rub the stick over the hole to stop the leak. The compound stick can even stop small leaks while the water is still running in the pipe. Epoxy paste can be applied only to dry pipes, and the water must be turned off. repair clamps An epoxy putty can be applied over the source of the leak to temporarily seal it. Immediately turn off the water supply upstream of the leaking pipes. Drain the water from the damaged line and ensure that the area to be patched is clean and dry so that the epoxy will properly adhere to the pipe.
Explanation: