What is the diffrence between a small block and a big block lets see if yall know

An archer releases an arrow toward a target. The arrow travels 166 meters in 2 seconds. The speed of the arrow is

gavmur [86]

Explanation:

speed= distance/time

=166/2

=83m/s

6 0

2 years ago

Which of the following statements about cylinder placement are true?

Alenkinab [10]

What is the following?

3 0

3 years ago

Create a C language program that can be used to construct any arbitrary Deterministic Finite Automaton corresponding to the FDA

otez555 [7]

Answer:

see the explanation

Explanation:

/* C Program to construct Deterministic Finite Automaton */

#include <stdio.h>

#include <DFA.h>

#include <stdlib.h>

#include <math.h>

#include <string.h>

#include <stdbool.h>

struct node{

struct node *initialStateID0;

struct node *presentStateID1;

};

printf("Please enter the total number of states:");

scanf("%d",&count);

//To create the Deterministic Finite Automata

DFA* create_dfa DFA(){

q=(struct node *)malloc(sizeof(struct node)*count);

dfa->initialStateID = -1;

dfa->presentStateID = -1;

dfa->totalNumOfStates = 0;

return dfa;

}

//To make the next transition

void NextTransition(DFA* dfa, char c)

{

int tID;

for (tID = 0; tID < pPresentState->numOfTransitions; tID++){

if (pPresentState->transitions[tID].condition(c))

{

dfa->presentStateID = pPresentState->transitions[tID].toStateID;

return;

}

dfa->presentStateID = pPresentState->defaultToStateID;

}

//To Add the state to DFA by using number of states

void State_add (DFA* pDFA, DFAState* newState)

{

newState->ID = pDFA->numOfStates;

pDFA->states[pDFA->numOfStates] = newState;

pDFA->numOfStates++;

}

void transition_Add (DFA* dfa, int fromStateID, int(*condition)(char), int toStateID)

{

DFAState* state = dfa->states[fromStateID];

state->transitions[state->numOfTransitions].toStateID = toStateID;

state->numOfTransitions++;

}

void reset(DFA* dfa)

{

dfa->presentStateID = dfa->initialStateID;

}

5 0

3 years ago

What is operant conditioning

Degger [83]

DescriptionOperant conditioning is a type of associative learning process through which the strength of a behavior is modified by reinforcement or punishment. It is also a procedure that is used to bring about such learning.

6 0

4 years ago

A plant manager randomly selects a can of peas from the assembly line and records whether or not the can's label is properly att

love history [14]

Complete Question

For each of the following experiments, identify the counting rule that is relevant for determining the number of experimental outcome.Then use the counting rules to determine the number of experimental outcome

First Experiment

A plant manager randomly selects a can of peas from the assembly line and records whether or not the can's label is properly attached , followed by the weight of the can (as less than 14 ounces, exactly 14, or more than 14 ounces).

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Second Experiment

Three branches (A,B, and C) of a bank have open manager positions. Three home-office employees from a pool of five are randomly selected to fill the manager positions. The first home-office employee selected becomes the manager of branch A, the second becomes the manager of branch B, and the third becomes manager of branch C.

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Third Experiment

A stockbroker forms a stock portfolio for a client by randomly selecting three stock from a pool of five.

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Answer:

First Experiment

Counting rule: Multiple-Step Experiments

Number of Experimental Outcomes: 6

Second Experiment

Counting rule: Permutations

Number of Experimental Outcomes: 60

Third Experiment

Counting rule: Combinations

Number of Experimental Outcomes: 10

Explanation:

The explanation of the first experiment is on the first uploaded image

For the second experiment the counting rule is permutation because from the experiment we can see that the order of selection is important

To obtain the Number of Experimental Outcomes:

We have:

$5p_{3} = \frac{5!}{2!}$

$= \frac{5*4*3*2!}{2!}$

$= 60$

For the third experiment the the counting rule is combination because the order of selection is not important

To obtain the Number of Experimental Outcomes:

We have:

$5C_{3} =\frac{5!}{3!2!}$

$= 10$

4 0

3 years ago