Question

A 23.9 g sample of CaSO4 is found to contain 7.04 g of Ca and 11.2 g of O. Find the mass of sulfur in a sample of CaSO4 with a mass of 49.5 g.

Answer 1

The mass of sulfur in 49.5 g of CaSO₄ is 11.7 g.

A 23.9 g sample of CaSO₄ is found to contain 7.04 g of Ca and 11.2 g of O. Considering that the sum of the masses of the elements is equal to the mass of the compound, the mass of S in 23.9 g of CaSO₄ is:

$mCaSO_4 =mCa + mS + mO\\mS = mCaSO_4 - mCa - mO\\mS = 23.9g - 7.04 g - 11.2 g = 5.66 g$

There are 5.66 g of S in 23.9 g of CaSO₄. The mass of S in 49.5 g of CaSO₄ is:

$49.5 g CaSO_4 \times \frac{5.66gS}{23.9 g CaSO_4} = 11.7 g S$

The mass of sulfur in 49.5 g of CaSO₄ is 11.7 g.

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