Question

Calculate [h3o ] of the following polyprotic acid solution: 0. 140 m h3c6h5o7

Answer 1

The value of concentration of H₃O⁺ of the polyprotic acid solution 0.140M H₃C₆H₅O₇ is 2.1×10⁻⁴M.

What is Ka?

Ka is the acid dissociation constant which shows its value in the equilibrium condition.

Given chemical reaction with ICE table is:

                          H₃C₆H₅O₇   →   C₆H₅O₆⁻   +   H₃O⁺

Initial:                    0.140                 0                  0

Change:                    -x                   +x                 +x

Equilibrium:         0.140-x                x                   x

Ka for the acid = (x)(x) / (0.140-x)

For the H₃C₆H₅O₇ acid value of Ka = 3.2 × 10⁻⁷

We can neglect the value of x from the term 0.140-x, as x is vey small as compared to 0.140 so that equation becomes,

3.2 × 10⁻⁷ = x² / 0.140

x = 2.1×10⁻⁴M

Hence the concentration of H₃O⁺ is 2.1×10⁻⁴M.

To know more about Ka, visit the below link:

brainly.com/question/3006391

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