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AfilCa [17]
1 year ago
13

What is the molarity of a solution that contains 3.4 moles of NaCL in 2.2 L of solution ?

Chemistry
1 answer:
jeka941 year ago
5 0

Answer:

what is the molarity of a solution that contains 3.4 moles of NaCL in 2.2 L of solution ?

Explanation:

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When 0.200 grams of Al reacts with 15.00 mL of a 0.500 M copper(II) chloride solution, how many moles of solid Cu would be produ
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When The balanced equation is:
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So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)
        
where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute: 
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So, CuCl2 is determining the no.of moles of the products.
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∴The no.of moles of Cu= 3*0.0025=  0.0075 moles.
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 = 0.0075 * 63.546 =0.477 g


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