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Leno4ka [110]
3 years ago
14

A liter of milk has mass of 1060 g and a 1,6 percent of mass in fat. Calculate the mass concentration of fat in g\L

Chemistry
2 answers:
Readme [11.4K]3 years ago
8 0

The milk has a mass concentration of 17 g/l of fat.

Anettt [7]3 years ago
3 0

Answer:

The mass concentration of fat is 16.96 \frac{g}{L}

Explanation:

The ratio between the mass of the solute and the mass of the resulting mixture is defined as percentage mass concentration (% m / m). This is:

percentage mass of solute=\frac{mass of solute}{mass of solution} *100

Then, in this cases the percent of mass in fat is:

1,6=\frac{x(g)}{1060g} *100

Isolating the value of x is obtained:

x=\frac{1,6*1060}{100} g

x= 16.96 g

Considering that:

mass concentration=\frac{mass of solute(g)}{volume of solution(l)}

Then:

mass concentration=\frac{16.96 g}{1 L}

mass concentration= 16.96 \frac{g}{L}

So, <u><em>the mass concentration of fat is 16.96 </em></u>\frac{g}{L}<u><em></em></u>

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Answer:

density = 8.9 g/ml

m = 20.5 g

V = ... ?

density = m/V

V = m / density

= 20.5 / 8.9

= 2.30337 ml

3 0
3 years ago
Why do most atoms form chemical bonds?
zloy xaker [14]

Answer:

Why do most atoms form chemical bonds? They want a full outer shell of electrons, so the lose, gain, or share electrons with other elements, forming compounds, until they have 8 valence electrons and become stable. Double and triple covalent bonds that have greater bond energy and are shorter than single bonds.

Explanation: HOPE THIS HELPS YOU..

3 0
3 years ago
Write the cell notation for an electrochemical cell consisting of an anode where Mn (s) is oxidized to Mn2 (aq) and a cathode wh
morpeh [17]

Answer:

Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)

Explanation:

In writing the cell notation for an electrochemical cell, the anode is written on the left hand side while the cathode is written on the right hand side. The two half cells are separated by two thick lines which represents the salt bridge.

For the cell discussed in the question; the Mn(s)/Mn^2+(aq) is the anode while the Co^2+(aq)/Co(s) half cell is the cathode.

Hence I can write; Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)

8 0
3 years ago
Helpppooo give answer thanks
DaniilM [7]

Answer:

625 mL

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 250 mL

Molarity of stock solution (M₁) = 5 M

Molarity of diluted solution (M₂) = 2 M

Volume of diluted solution (V₂) =?

The volume of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

5 × 250 = 2 × V₂

1250 = 2 × V₂

Divide both side by 2

V₂ = 1250 / 2

V₂ = 625 mL

Therefore, the volume of the diluted solution is 625 mL.

8 0
3 years ago
Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the
Vera_Pavlovna [14]

2NH₂ + O₂ → N₂ + 2H₂O

<u>Explanation:</u>

Balancing the equation means, the number of atoms on both sides of the equation must be the same.

In the case of the given equation, we have to find out whether it is balanced or not.

2NH₂ + O₂ →  N₂ + 2H₂O

Atoms       Number of atoms before balancing     after balancing

                 LHS                 RHS                                    LHS         RHS

N               1                        2                                            2              2

H               2                       2                                            4              4                        

O               2                       1                                            2                2

To balance the N atoms, we have to put 2 in front of NH₂, and then to balance the H, O atoms, we have to put 2 in front of H₂O, so that each atom in left hand as well as right hand side of the equation was balanced.

8 0
3 years ago
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