Question

A liter of milk has mass of 1060 g and a 1,6 percent of mass in fat. Calculate the mass concentration of fat in g\L

Answer 1

The milk has a mass concentration of 17 g/l of fat.

Answer 2

Answer:

The mass concentration of fat is 16.96 $\frac{g}{L}$

Explanation:

The ratio between the mass of the solute and the mass of the resulting mixture is defined as percentage mass concentration (% m / m). This is:

$percentage mass of solute=\frac{mass of solute}{mass of solution} *100$

Then, in this cases the percent of mass in fat is:

$1,6=\frac{x(g)}{1060g} *100$

Isolating the value of x is obtained:

$x=\frac{1,6*1060}{100} g$

x= 16.96 g

Considering that:

$mass concentration=\frac{mass of solute(g)}{volume of solution(l)}$

Then:

$mass concentration=\frac{16.96 g}{1 L}$

$mass concentration= 16.96 \frac{g}{L}$

So, the mass concentration of fat is 16.96 $\frac{g}{L}$