The percentage of glucose given is m/v. This means that the given percentage of volume consists of mass.
In this solution, percentage of glucose is 5.5% m/v.
This means that 5.5% of the volume is the mass of glucose.
Given volume is 285 mL.
Therefore mass of glucose is 5.50% of 285 mL = (5.5*285)/100
mass of glucose = 15.67 g
<u>Answer:</u> The standard Gibbs free energy of the given reaction is 6.84 kJ
<u>Explanation:</u>
For the given chemical equation:

The expression of
for above equation follows:

We are given:

Putting values in above expression, we get:

To calculate the equilibrium constant (at 25°C) for given value of Gibbs free energy, we use the relation:

where,
= standard Gibbs free energy = ?
R = Gas constant = 8.314 J/K mol
T = temperature = ![25^oC=[273+25]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B273%2B25%5DK%3D298K)
= equilibrium constant at 25°C = 0.0632
Putting values in above equation, we get:

Hence, the standard Gibbs free energy of the given reaction is 6.84 kJ
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A substance's molar mass is calculated by multiplying its relative atomic mass by the molar mass constant (1 g/mol). ... By multiplying a given mass by the molar mass, the amount of moles of the substance can be calculated.