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Murrr4er [49]
2 years ago
12

3 Why does the frequency of a wave increase as the wavelength decreases?

Physics
1 answer:
HACTEHA [7]2 years ago
8 0
3A) Because the wave speed remains constant
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Two trains, each having a speed of 35 km/h, are headed at each other on the same straight track. A bird that can fly 70 km/h fli
aalyn [17]

Answer:

Explanation:

The two train are traveling at 35km/hr

A bird starts from one of the train and travel at 70km/hr

The distance between the two train is 70km.

The bird is going to and fro, so since we know the speed of the bird, we only need to know the time the two train will collide

So let calculate the time the two train will meet

Since each train is traveling at 35km/hr

The train will collide at mid point of their distance apart, so let know the time each of the train will get their

Time to each train will get to 35km

Velocity =distance/time

Time =distance/velocity

Time=35/35

Time = 1hour

Therefore, the bird will fly for 1hr before been crushed down by the train

Since the bird is traveling at 70km/hr

Therefore total distance the bird will travel

Distance = velocity × time

Distance = 70 ×1

Distance =70km

So the bird will travel for 70km.

8 0
3 years ago
A 67.6-kg boy is surfing and catches a wave which gives him an initial speed of 1.56 m/s. He then drops through a height of 1.65
sveticcg [70]

Answer:

The nonconservative work was done on the boy is 1154.87 J.

Explanation:

Given;

mass of the boy, m = 67.6 kg

initial speed of the boy, u = 1.56 m/s

height of fall, h = 1.65 m

final speed of the boy, v = 8.30 m/s

The initial energy of the boy is given by;

E₁ = K.E₁ + P.E₁

E₁ = ¹/₂mu² + mgh

E₁ = ¹/₂(67.6)(1.56)² + (67.6 x 9.8 x 1.65)

E₁ = 82.134 + 1091.475

E₁ = 1,173.61 J

The final energy of the boy is given by;

E₂ = K.E₂

E₂ = ¹/₂mv²

E₂ = ¹/₂(67.6)(8.3)²

E₂ = 2,328.482 J

The nonconservative work was done on the boy is given by;

W = E₂- E₁

W = 2,328.482 J - 1,173.61 J

W = 1154.87 J

Therefore, the nonconservative work was done on the boy is 1154.87 J.

5 0
3 years ago
A child lies on his back and raises his head up off the floor. When doing so, the total tension force in his neck muscles is 51.
Margarita [4]

Answer:

The total tension in the child's neck muscle, T = 56.51 N

Explanation:

Let m = mass of the child's neck

Radius of the curve, r = 2.40 m

The child's speed, v = 3.35 m/s

The tension force on the child's neck when he raises his head up off the floor, T_{f} = 51.0 N

The tension force on the child's neck when he raises his head from the wall of the slide, T_{s} = ?

T_{f} = mg\\g = 9.8 m/s^2\\51 = m * 9.8\\m = 51/9.8\\m = 5.2 kg

Since he makes a circular turn in water, the radial acceleration can be given by the equation:

a_{r} = \frac{v^{2} }{r} \\a_{r} = \frac{3.35^{2} }{2.4}\\a_{r} = 4.68 m/s^2

T_{s} = ma_{r} \\T_{s} = 5.2 * 4.68\\T_{s} = 24.336 N

The total tension in the child's neck muscle till be calculated as:

T = \sqrt{T_{f} ^{2} + T_{s} ^{2} } \\T = \sqrt{51 ^{2} + 24.336^{2} }\\T = \sqrt{2601 + 592.24 }\\T = 56.51 N

5 0
2 years ago
You toss a rock up vertically at an initial speed of 39 feet per second and release it at an initial height of 6 feet. The rock
3241004551 [841]

Answer:

2.583 s, 29.77 ft and 1.219 s

Explanation:

Using equation of motion and taken the motion upward as positive, also a = g ( acceleration due to gravity) = - 32 fts⁻², V= 39 fts⁻¹ V₁ is final velocity, y is the distance in ft from the ground

H = 6 ft, the height from which it is tossed

V₁ = V + gt = V - gt

at maximum height the body came to rest momentarily V₁ = 0

0 = V - gt

-V = -gt

- 39 / -32 = t

t time to reach maximum height = 1.219 s

To Maximum height reached can be calculated with the formula

V₁² = V² + 2g( y - H) where H is the initial height reached by the tossed rock

where V₁ is the final velocity at maximum height which = 0

0 = V² - 2g(y-H) where y is the distance traveled from the ground

-V² = -2g(y-H)

₋V² / -2g = y-H

(V²/2g) + H = y in ft

(39² / (2 × 32)) + 6

y = 29.77 ft

The total time it will be in air can be calculated with the formula below

y = H + Vt - 0.5gt² from y-H = ut + 0.5at²

0.5gt² - Vt - H = 0 since the body returned to the ground ( y = 0)

0.5gt² - Vt - H = 0

using quadratic formula

- (-V)² ± √ ((-V²) - 4 × 0.5g × -H) / (2 × 0.5 × g)

(V ± √ (V² + 2gH)) ÷ g

substitute the values into the expression

t = (39 + √(39² + (2×-32× 6)))/ 32 or (39 - √ (39² + (2 × -32×6))/ 32

t = (39 + √(1521 +384))/32 = (39 + √1905) / 32  = 2.583 s

t = (39 - √1905) / 32 =  -0.15 s

The will remain in air (V ± √ (V² + 2gH)) / g seconds. It will reach a maximum height of (V²/2g) + H feet after V/g seconds

8 0
2 years ago
A helicopter is traveling with a velocity of 12 m/s directly upward.
Irina-Kira [14]

Answer:

H = 27.35 m

Explanation:

From projectile motion, we know that;

h = (v_o)²/2g

Where;

v_o = 12 m/s

g = 9.8 m/s²

Thus;

h = 12²/(2 × 9.8)

h = 144/19.6

h = 7.35 m

Now, we are told that when the man is 20 m above the pillow, he lets go of

the rope.

Thus, greatest height reached by the man above the ground is;

H = 20 + h

H = = 20 + 7.35

H = 27.35 m

5 0
3 years ago
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