<span>How many moles of acetic acid and of sodium acetate are present in 50.0 mL of solution?
We calculate it as follows:
moles of acetic acid = .120 mol/L (.050 L ) = 0.006 mol
moles of sodium acetate = 0.150 mol/L (0.050 L) = 0.008 mol
Hope this answers the question. Have a nice day.</span>
Answer:
The vapor pressure for the first solution at 20°C is 17.48 Torr.
The vapor pressure for the second solution at 20°C is 17.49 Torr.
Explanation:
1) mass of solute that is glucose = 10 g
Moles of glucose ,
Mass of water = m
Volume of water = V = 1L = 1000 mL
Density of water = 1 g/ml
Moles of water =
Vapor pressure of the solution =
Vapor pressure of the pure solvent that is water =
Mole fraction of solute=
The vapor pressure for the first solution at 20°C is 17.48 Torr.
2 ) mass of solute that is sucrose= 10 g
Moles of sucrose ,
Mass of water = m
Volume of water = V = 1L = 1000 mL
Density of water = 1 g/ml
Moles of water =
Vapor pressure of the solution =
Vapor pressure of the pure solvent that is water =
Mole fraction of solute=
The vapor pressure for the second solution at 20°C is 17.49 Torr.
P1/T1 = P2/T2
125⁰C = 398.15 k
182⁰C = 455.15 k
1.22/398.15 = p2/455.15
p2= 1.39atm
the pressure of the gas be after the temperature change is 1.39 atm
Answer:
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