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2 years ago

What are the difference between malachite and pyrite and how they are alike

Chemistry

1 answer:

Anna11 [10]2 years ago

3 0

We can confirm that malachite and pyrite are similar in that they are both carbonate minerals, they differ however in chemical composition and characteristics.

<h3>What is malachite and pyrite?</h3>

Pyrite is a form of iron sulfide. This mineral has come to be known as the fool's gold, for its striking resemblance to gold. Malachite, on the other hand, has been known to closely resemble emeralds and is often used as a gemstone. They are both carbonate minerals, but malachite is copper-based, giving it a different chemical composition and properties.

Therefore, we can confirm that malachite and pyrite are similar in that they are both carbonate minerals, they differ however in chemical composition and characteristics.

To learn more about minerals visit:

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Answer:

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2 years ago

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If 2.9g of water is heated from 23.9C to 98.9C, how much heat (in calories) was added to the water?

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Answer:

Explanation:

we know that

ΔH=m C ΔT

where ΔH is the change in enthalpy (j)

m is the mass of the given substance which is water in this case

ΔT IS the change in temperature and c is the specific heat constant

we know that given mass=2.9 g

ΔT=T2-T1 =98.9 °C-23.9°C=75°C

specific heat constant for water is 4.18 j/g°C

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3 years ago

A 25 gram(m) metal ball is heated to 200C(delta T) with 2330 Joules(q) of energy. What is the specific heat of the metal?

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Answer:

The specific heat of the metal is 0.466 $\frac{J}{g*C}$

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

Q= 2330 J
c= ?
m= 25 g
ΔT= 200 °C

Replacing:

2330 J= c*25 g* 200 °C

Solving:

$c=\frac{2330 J}{25 g* 200 C}$

c=0.466 $\frac{J}{g*C}$

<u><em>The specific heat of the metal is 0.466 </em></u> $\frac{J}{g*C}$ <u><em></em></u>

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A solution with [ OH] of 5 x 10-3 has a pH of

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Answer:

11·699

Explanation:

Given the concentration of hydroxide ion in the solution is 5 × $10^{-3}$ M

Assuming the temperature at which it is asked to find the pH of the solution be 298 K

<h3>At 298 K the dissociation constant of water is $10^{-14}$ </h3><h3>∴ pH + pOH = 14 at 298 K</h3><h3>pOH of the solution = -log( concentration of hydroxide ion )</h3>

∴ pOH of the given solution = - log(5 × $10^{-3}$ = -0·699 + 3 = 2·301

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