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ipn [44]
3 years ago
9

According to Newton’s law of universal gravitation, which statement is true?

Physics
2 answers:
olasank [31]3 years ago
6 0

A) Falling objects accelerate as they approach the ground.

True

Reason : as the falling object approach the ground, acceleration due to gravity in down direction acts on it and accelerate it.

B) The weight of an object increases as it moves away from the ground.

False

Reason : As the object moves away from the ground, acceleration due to gravity acting on the object decreases. since the weight directly depends on the acceleration due to gravity, hence the weight decreases too.

C) Lighter objects experience a lower acceleration than heavier objects.

False

Reason : Since acceleration due to gravity is independent of the mass.

D) The mass of an object increases as it moves closer to the ground.

False

Reason : Since mass of an object is independent of the acceleration due to gravity.

SIZIF [17.4K]3 years ago
4 0

Option (a) is correct.

Falling objects accelerate as they approach the ground.This is because of the force of gravity acting on the falling objects. so the velocity of these objects increases continuously as they approach the ground. the acceleration acting on the falling objects is a constant ( close to the surface of earth) and is called as acceleration due to gravity denoted by g. value of g=9.8 m/s².

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the I'm pact force of 0.5 is lol u guys go and study why r u asking answers

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A bowler applies 14 N of force to a 4.5 kg bowling<br> ball. Find the ball's acceleration.
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Answer:

F=m(a)  3.111

Explanation:

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To the nearest tenth, what is the area of the shaded segment when JA=8ft ??
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Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that
elena-s [515]

Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

E_p = 4.74 *10^(-12) eV

E_k = 490 eV

Explanation:

part a

The potential difference between two plates = 490 V

Distance between two plates = 8.5 cm

Answer: The positive plate is at higher potential because of convention.

part b

Electric Field between the plates

E = V / d

E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

W = V*q

W = 490 * 1.602*10^-19

W = 7.85 * 10^-17 J

or W = 490 eV

Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p =  9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

Very very small E_p approximately 0

Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

E_k = 490eV - 4.74*10^(-12)eV

E_k = 490 eV

Answer: Kinetic Energy of an electron gained E_k = 490 eV

7 0
4 years ago
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1) 2 kilograms converted into grams is 2000

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