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kondor19780726 [428]
2 years ago
5

When two forces act in opposite directions, then net force acting due to two

Physics
2 answers:
vladimir1956 [14]2 years ago
6 0

Answer:

option b

Explanation:

when the two forces act in opposite directions there effective magnitude decreases.

dusya [7]2 years ago
4 0

Answer:

b. difference between two factors

Explanation:

When two forces act in the opposite directions, the net force is the difference between them.

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Create a mathematical model for the pressure variation as a function of position and time for a sound wave, given that the wavel
goblinko [34]

Answer:

The equation of position and time for a sound wave is \Delta p=0.270(33.06 x-11342.40 t).

Explanation:

Given that,

Wavelength = 0.190 m

Maximum pressure \Delta P_{max}= 0.270 N/m^2

We know that,

The function of position and time for a sound wave,

\Delta p=\Delta p_{max}(kx-\omega t)....(I)

We need to calculate the frequency

Using formula of frequency

f=\dfrac{v}{\lambda}

Put the value into the formula

f=\dfrac{343}{0.190}

f=1805.2\ Hz

We need to calculate the angular frequency

Using formula of angular frequency

\omega =2\pi f

Put the value into the formula

\omega=2\pi\times1805.2

\omega=11342.40\ rad/s

We need to calculate the wave number

Using formula of wave number

k = \dfrac{2\pi}{\lambda}

Put the value into the formula

k=\dfrac{2\pi}{0.190}

k=33.06

Now, put the value of k and ω in the equation (I)

\Delta p=0.270(33.06 x-11342.40 t)

Hence, The equation of position and time for a sound wave is \Delta p=0.270(33.06 x-11342.40 t).

3 0
3 years ago
Factors that affect the force of gravity between objects include their distance apart and their
mr_godi [17]

Answer:

factors that affect the force of gravity between objects include their distance apart and their mass.

Explanation:

6 0
3 years ago
A football player kicks a ball at a 30o angle from the ground with an initial velocity of 15 m/s. What is the final velocity of
navik [9.2K]

Given that,

Angle = 30°

Initial velocity = 15 m/s

We need to calculate the time of flight

Using formula of time of flight

T=\dfrac{2u\sin\theta}{g}

Where, u = initial velocity

g = acceleration due to gravity

Put the value into the formula

T=\dfrac{2\times15\sin30}{9.8}

T=1.5\ sec

We need to calculate the final velocity of the ball

Using equation of motion

v=u+gt

v=15+9.8\times1.5

v=29.7\ m/s

Hence, The final velocity of the ball is 29.7 m/s.

7 0
4 years ago
Find the sum of the vectors:11 km N ,11km E
vladimir1956 [14]

The resultant vector is 11√2 km due north east.

<h3><u>Explanation:</u></h3>

The vector is a type of quantity which has both magnitude and direction. This quantities when expressed needs to specify both magnitude and direction.

We need to calculate the magnitude and direction separately.

Here firstly for the magnitude,

The magnitudes are both 11 km and they are at right angles to each other.

So, the resultant magnitude = √(11² +11²) km

=11√2 km

Now for the direction, one vector is due north and the other is due east.

So the resultant vector is due north east.

So the final vector is 11√2 km due North-East.

6 0
3 years ago
My Notes Ask Your Teacher 6. Six blocks with different masses, m, each start from rest at the top of smooth, frictionless inclin
Tresset [83]

Answer:

Kf > Ka = Kb > Kc > Kd > Ke

Explanation:

We can apply

E₀ = E₁

where

E₀: Mechanical energy at the beginning of the motion (top of the incline)

E₁: Mechanical energy at the end (bottom of the incline)

then

K₀ + U₀ = K₁ + U₁

If v₀ = 0  ⇒  K₀

and  h₁ = 0   ⇒    U₁ = 0

we get

U₀ = K₁    

U₀ = m*g*h₀ = K₁

we apply the same equation in each case

a) U₀ = K₁ = m*g*h₀ = 70 Kg*9.81 m/s²*8m = 5493.60 J

b) U₀ = K₁ = m*g*h₀ = 70 Kg*9.81 m/s²*8m = 5493.60 J

c) U₀ = K₁ = m*g*h₀ = 35 Kg*9.81 m/s²*4m = 1373.40 J

d) U₀ = K₁ = m*g*h₀ = 7 Kg*9.81 m/s²*16m = 1098.72 J

e) U₀ = K₁ = m*g*h₀ = 7 Kg*9.81 m/s²*4m = 274.68 J

f) U₀ = K₁ = m*g*h₀ = 105 Kg*9.81 m/s²*6m = 6180.30 J

finally, we can say that

Kf > Ka = Kb > Kc > Kd > Ke

8 0
3 years ago
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