Answer:
lauda and lasan I am fine with me lit Q ans pg-14
Answer:
Time taken to cover the distance 11.45 s.
Explanation:
The given parameters:
Initial Velocity(u)=24 m/s
Acceleration (a)=8
Distance or Displacement(s)=800 m
Displacement or Distance is equal in the above because it travels in a straight line.
We have to apply Second Equation of Motion,
s=ut+
800=24t + 4
200=6t +
+ 6t - 200=0
Solving, the quadratic equation to find out the roots, we get that the possible values of t will be 11.45 s and a negative value.
The negative value will be neglected as time cannot be negative.
Hence, the time taken is 11.45 s.
Answer:
(a) 50 kJ
(b) 14.14 m/s
(c) 0 N
(d) 0 J
Solution:
As per the question:
Mass of car, m = 500 kg
Force, F = 1000 N
Distance traveled, s = 50 m
Now,
(a) The total work done can be given as:
(b) To calculate the speed of the car:
Using work-energy relation, we can say that the work done equals the change in the kinetic energy of the car:
where
v' = final velocity
v = initial velocity = 0
Now,
(c) To calculate the net force on the car when the velocity is constant:
The net force is given as the product of mass and acceleration:
F = ma
<em>Acceleration can be defined as the rate with which the velocity of the car changes and the since the velocity is constant, the car will not have any acceleration, a = 0</em>
Thus the net force is also zero.
(d) The total work done when the car moves with constant velocity:
They both have exactly the same acceleration.
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