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earnstyle [38]
2 years ago
8

Find the initial velocity of a car which stops in 10sec, after applying brakes at the rate of 2m/s²

Physics
1 answer:
Dennis_Churaev [7]2 years ago
7 0

Answer:

20\ m/s

Explanation:

Since we are given time, acceleration, and final velocity, we can use the following formula to find the initial velocity:

v_f = v_i + at

Our given values:

v_f = 0\\a = -2\\t = 10\\

<em>Acceleration is negative because the car is slowing down.</em>

Add the values to the formula, and solve for v_i:

v_f = v_i + at\\0 = v_i + (-2)(10)\\0 = v_i -20\\20 = v_i

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A string that is under 54.0 N of tension has linear density 5.20 g/m . A sinusoidal wave with amplitude 2.50 cm and wavelength 1
kicyunya [14]

Answer:

8.89288275 m/s

Explanation:

F = Tension = 54 N

\mu = Linear density of string = 5.2 g/m

A = Amplitude = 2.5 cm

Wave velocity is given by

v=\sqrt{\frac{F}{\mu}}\\\Rightarrow v=\sqrt{\frac{54}{5.2\times 10^{-3}}}\\\Rightarrow v=101.90493\ m/s

Frequency is given by

f=\frac{v}{\lambda}\\\Rightarrow f=\frac{101.90493}{1.8}\\\Rightarrow f=56.61385\ Hz

Angular frequency is given by

\omega=2\pi f\\\Rightarrow \omega=2\pi 56.61385\\\Rightarrow \omega=355.71531\ rad/s

Maximum velocity of a particle is given by

v_m=A\omega\\\Rightarrow v_m=0.025\times 355.71531\\\Rightarrow v_m=8.89288275\ m/s

The maximum velocity of a particle on the string is 8.89288275 m/s

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2 years ago
A child rides the train at Disneyland which takes him in a loop around the amusement park at a speed of 3 m/s. Which statement b
velikii [3]
The velocity is a vectorial quantity, whereas speed is a scalar quantity, meaning it depends on the direction!
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6 0
3 years ago
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When you improve your the ability of your muscles to repeatebly exert themselves you are improving your?
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It is muscular endurance.

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3 years ago
A 100 kg box is suspended from two ropes. The "left rope makes an angle of 20" degrees with the vertical, and the right rope mak
GarryVolchara [31]

Explanation:

It is given that,

Mass of the box, m = 100 kg          

Left rope makes an angle of 20 degrees with the vertical, and the right rope makes an angle of 40 degrees.  

From the attached figure, the x and y component of forces is given by :

T_{1x} =-T_1 cos (20)

T_{2x} = T_2 cos (40)

mg_x = 0

T_{1y} = T_1 sin (20)

T_{2y} = T_2 sin (40)

mg_y= -mg

Let R_x and R_y is the resultant in x and y direction.

R_x=-T_1 cos (20)+T_2 cos (40)+0

R_y=T_1 sin(20)+T_2 sin(40)-mg

As the system is balanced the net force acting on it is 0. So,

-T_1 cos (20)+T_2 cos (40)+0=0.............(1)

T_1 sin(20)+T_2 sin(40)-100\times 9.8=0..................(2)

On solving equation (1) and (2) we get:  

T_1=866.86\ N (tension on the left rope)

T_2=1063.36\ N (tension on the right rope)

So, the tension on the right rope is 1063.36 N. Hence, this is the required solution.                            

7 0
3 years ago
Calculating heat gained or lost requires mass, specific heat, and
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<span>Calculating heat gained or lost requires mass, specific heat, and

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