Answer:
120,000J
Corrected question;
In one hour, coal supplies 500 000 J of energy. The wasted energy amounts to 380 000 J. How much useful energy is produced in one hour?
Explanation:
Given;
Total energy Et = 500,000 J
Wasted Energy Ew = 380,000J
The amount useful energy is the amount of energy that is available for supply.
This can be derived by subtracting the wasted energy from the total energy.
Useful energy = Total Energy - wasted energy
Eu = Et - Ew
Substituting the given values;
Eu = 500,000J - 380,000
Eu = 120,000 J
The amount of useful energy produced in one hour is 120,000 J
Object Motion: 25 m/s
Circumference of Circle:
1/4 Circumference of Circle in 1 second = 25 meters
25 meters times 4 = Circumference of Circle
Circumference = 100 meters
Formula to Find Circumference of Circle: (work opposite)
C = 2<span>πr
100 = </span>2πr divided
100/2π = r simplify
50/π = r (exact radius)
Answer:
50/π meters = r (exact radius)
Answer:
The time is 
Explanation:
From the question we are told that
The period of the circuit is 
Generally voltage maximization of the capacitor occurs during the voltage minimization of the inductor and vise versa
So the time between the voltage maximization of the capacitor and that of the inductor is mathematically represented as
=> 
=>
Energy can neither be created nor be destroyed.
For the purpose we will use the following equation for potential energy:
U = m * g * h
In the above equation, m represents the mass of the object, h represents the height of the object and g represents the gravitational field strength (9.8 N/kg on Earth).
When we plug values into the equation, we get following:
U= 65.7kg * 9.8 N/kg *135m = 86921.1 J = 86.92 kJ
