Answer:
V = -1.33 m/s
Explanation:
Given,
The mass of the camper, m = 100 kg
The velocity of the camper, v = 3.0 m/s
The combined mass of canoe and another camper, M = 225 kg
The velocity of the combined canoe and another camper, V = ?
According to the law of conservation of momentum,
MV + mv = 0 (Since the initial momentum of the dock is 0)
V = -mv/M
= -100 x 3/225
= -1.33 m/s
The negative sign indicates that the combined objects moves opposite to that of the camper.
Hence, the velocity of the combined canoe and camper is, V = -1.33 m/s
The cart comes to rest from 1.3 m/s in a matter of 0.30 s, so it undergoes an acceleration <em>a</em> of
<em>a</em> = (0 - 1.3 m/s) / (0.30 s)
<em>a</em> ≈ -4.33 m/s²
This acceleration is applied by a force of -65 N, i.e. a force of 65 N that opposes the cart's motion downhill. So the cart has a mass <em>m</em> such that
-65 N = <em>m</em> (-4.33 m/s²)
<em>m</em> = 15 kg
I want to improve my speed
