Electric field strength = resistivity of copper x current density
where
p= 1.72 x 10^-8 <span>ohm meter
diameter = 2.05mm=.00205 m
current = 2.75 A
</span>get first the current density:
current density = current/ cross section area
find the cross section area
cross section area = pi.(d/2)^2;
cross section = 3.3 006x10-6 m^2
substitute the values
current density = 2.75A/3.3006x 10-6m^2
current density=35.55 x1 0^2 A/m^2
Electric field stregnth =1.72 x 10^-8 ohm meter x 35.55 x10^2 A/m^2
Electric field stregnth= 46.415 Volts/m
The electric field strength of copper is 46.415 V/m.
Resistance = (voltage) / (current)
For this piece of wire . . .
Resistance = (61 volts) / (6 Amperes)
Resistance = (61/6) (V/A)
<em>Resistance = (10 and 1/6) ohms</em>
Since you know the voltage and current, the length doesn't matter.
The correct answer is option (C) the temperature of the shirt will increase because all wavelengths of light are absorbed by the shirt.
The relationship of heat and light
- Heat is a measure of the movement of particles in the body, the more particles move, the warmer the body becomes.
- When the body absorbs light radiation, its particles vibrate in accordance with the electromagnetic radiation's wavelengths, which causes an increase in the temperature with the increase in particle movement.
- The more wavelengths of radiation absorbed by an object, produces more heat.
Learn more about the Wavelength of light with the help of the given link:
brainly.com/question/13961990
#SPJ4
Answer:
18.6012339739 A
Explanation:
= Vacuum permeability = 
L = Length of wire = 55 cm
N = Number of turns = 4000
I = Current
Magnetic field is given by
The current necessary to produce this field is 18.6012339739 A
Answer
D.Diffraction
Explanation
Diffraction is a property that is experienced by waves when they come across a barrier when they are in motion.
The ways tends to curve behind the barrier. This is called diffraction of waves.
Now, sound is a wave and it also experience diffraction. . So the brother will be able to hear the sound due to diffraction
