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Minchanka [31]
2 years ago
14

A lamp is marked 24V, 100W. Describe an experiment to check that the electrical power supplied to the lamp is 100W when the p.d.

across it is 24V.
In your account you should
* include a circuit diagram,
* state the readings that are taken,
* show how the result is calculated from the readings.​
Physics
1 answer:
topjm [15]2 years ago
3 0

The electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.

<h3>What is electrical power?</h3>

Electrical power is the rate at which electrical work is done.

The unit of electrical power is Watts.

  • Power = Current × Voltage

The experiment will require a 24V Battery, a Lamp marked 24V, 100 W, a key, wires, a rheostat, a voltmeter and an ammeter.

The circuit is completed and the rheostat is adjusted to provide until the voltmeter reads 24V.

The ammeter reading is taken as well.

When the voltmeter reading is 24V, it can be seen that' the ammeter reading for current is approximately 4.2 A.

Calculating, the power of the lamp:

Power = 24 × 4.2 = 100 W

Therefore, the electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.

Learn more about power and p.d. at: https://brainly.in/question/13629965

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When light travels from a medium with higher refractive index to a medium with lower refractive index, there is a critical angle after which all the light is reflected (so, there is no refraction).

The value of this critical angle can be derived by Snell's law, and it is equal to
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In our problem, n1=1.47 and n2=1.33, so the critical angle is
\theta_C = \arcsin( \frac{1.33}{1.47} )=\arcsin (0.91)=65^{\circ}
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