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3 years ago

Calculate the de Broglie wavelength of an electron traveling at 2.0 x 10^8 m/s (me = 9.1*10^-31 kg).

Physics

1 answer:

timofeeve [1]3 years ago

4 0

Answer:

$\lambda=3.64\times 10^{-12}\ m$

Explanation:

We have,

Speed of an electron is $2\times 10^8\ m/s$

It is required to find the De Broglie wavelength of electron. The formula for the De- Broglie wavelength is given by :

$\lambda=\dfrac{h}{mv}$

h is Planck's constant

m is mass of an electron

Plugging all the values we get :

$\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^{8}}\\\\\lambda=3.64\times 10^{-12}\ m$

So, the De-Broglie wavelength of an electron is $3.64\times 10^{-12}\ m$

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2 years ago

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3 years ago

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WINSTONCH [101]

Answer:

$r=200m$

Explanation:

From the question we are told that:

Charges:

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Distance $d=300m$

Generally the equation for Force is mathematically given by

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3 years ago

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2 years ago

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