Question

Calculate the de Broglie wavelength of an electron traveling at 2.0 x 10^8 m/s (me = 9.1*10^-31 kg).

Answer 1

Answer:

$\lambda=3.64\times 10^{-12}\ m$

Explanation:

We have,

Speed of an electron is $2\times 10^8\ m/s$

It is required to find the De Broglie wavelength of electron. The formula for the De- Broglie wavelength is given by :

$\lambda=\dfrac{h}{mv}$

h is Planck's constant

m is mass of an electron

Plugging all the values we get :

$\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^{8}}\\\\\lambda=3.64\times 10^{-12}\ m$

So, the De-Broglie wavelength of an electron is $3.64\times 10^{-12}\ m$