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Wittaler [7]
4 years ago
6

Which statement best describes perigee?

Physics
1 answer:
algol134 years ago
7 0
<span>
A. The closet point in the Moon's orbit to Earth . . . . . perigee

B. The farthest point in the Moon's orbit to Earth . . . . . apogee

C. The Sun's orbit that is closest to the Moon . . . . . a meaningless description

D. The closest point in Earth's orbit of the Sun . . . . . perihelion

--  The farthest point in Earth's orbit of the Sun . . . . . aphelion
 </span>
You might be interested in
Two dump trucks each have a mass of 1,500 kg. The distance of the dump truck
xxTIMURxx [149]

Answer:

6.00 x 10⁻⁸N

Explanation:

Given parameters:

Mass of each dump trucks  = 1500kg

Distance between them  = 50m

Unknown:

New gravitational force between them = ?

Solution:

From Newton's law of universal gravitation,

        F = \frac{G m1 m2}{r^{2} }  

F is the gravitational force

G is the universal gravitation constant

m is the mass

r is the distance

           F  = \frac{6.67 x 10^{-11} x 1500  x 1500}{50^{2} }    = 6.00 x 10⁻⁸N

4 0
3 years ago
WILL GIVE BRAINLIEST AND 30 POINTS!
mariarad [96]

Answer:

Gallium

Explanation:

Gallium is one such element used as a do/pant in a p-type semiconductor.

A do/pant is an impurity added to a semi-conductor used to alter its properties. Semi-conductors have a wide range of applications. They will conduct heat and electricity only under certain conditions. This property is highly desirable and find a wide application in electronics.

For p-type conductors, they are best do/ped with elements with 3 valence electrons. These are group 3 elements. From the choices, only gallium belongs to this group.

Other elements given are good do/pants for n-type semiconductors. They have 5 valence electrons.

8 0
4 years ago
to 10 Hz. Superimposed on this signal is 60-Hz noise with an amplitude of 0.1 V. It is desired to attenuate the 60-Hz signal to
givi [52]

Answer:

G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1

If we square both sides we got:

G^2 (1+\frac{f}{f_c})^{2n}= 1

We divide both sides by G^2 and we got:

(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}

Now we can apply log on both sides and we got:

2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})

And solving for n we got:

n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}

And replacing we got:

n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}

n = \frac{4.60517}{3.8918}=1.18

And since n needs to be an integer the correct answer would be n=2 for the filter order.

Explanation:

For this case we can use the formula for the Butterworth filter gain given by:

[tec] G = \frac{1}{\sqrt{1 +(\frac{f}{f_c})^{2n}}}[/tex]

Where:

G represent the transfer function and we want that G =0.1 since the desired signal is less than 10% of it's value

f_c = 10 Hz represent the corner frequency

f= 60 Hz represent the original frequency

n represent the filter order and that's the variable that we need to find

G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1

If we square both sides we got:

G^2 (1+\frac{f}{f_c})^{2n}= 1

We divide both sides by G^2 and we got:

(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}

Now we can apply log on both sides and we got:

2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})

And solving for n we got:

n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}

And replacing we got:

n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}

n = \frac{4.60517}{3.8918}=1.18

And since n needs to be an integer the correct answer would be n=2 for the filter order.

7 0
3 years ago
A car travelling at 10 m/s accelerates at 3 m/s^2 for 6 seconds. What is the final velocity of the car?
tankabanditka [31]

Answer:28m/s

Explanation:I got one point so yeah hope this help

7 0
3 years ago
What happens when you boil seawater(no copying)
geniusboy [140]

Answer:

The water turns in to vapor and rises in the air leaving the salt  behind

Explanation:

8 0
3 years ago
Read 2 more answers
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