A student moves a horseshoe magnet by hand across a tabletop to varying distances from an electromagnet, as shown in the diagram
above.
The student records observations of how much force it takes to hold the horseshoe magnet in place at each distance. Observations
• 20 cm: no force required
• 10 cm: small force required; easy to hold in place
• 5 cm: large force required; very difficult to hold in place
What do the student's observations demonstrate?
A. The electromagnet's magnetic field becomes stronger as more magnetic material is added to it.
B. The electromagnet's magnetic field is stronger as more turns are added to the wire on the nail.
C. The electromagnet's magnetic field becomes stronger as a small amount of strength is added to the system by the battery.
D. The electromagnet's magnetic field is stronger close to it than far from it.
The student records observations of how much force it takes to hold the horseshoe magnet in place at each distance. Observations
• 20 cm: no force required
• 10 cm: small force required; easy to hold in place
• 5 cm: large force required; very difficult to hold in place
What do the student's observations demonstrate?
A. The electromagnet's magnetic field becomes stronger as more magnetic material is added to it.
B. The electromagnet's magnetic field is stronger as more turns are added to the wire on the nail.
C. The electromagnet's magnetic field becomes stronger as a small amount of strength is added to the system by the battery.
D. The electromagnet's magnetic field is stronger close to it than far from it.
2 answers:
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Answer:
The answer is ""
Explanation:
Answer:
Explanation:
Acceleration is defined as the change in velocity divided by the time it took to produce such change. The formula then reads:
Where Vf is the final velocity of the object, (in our case 80 m/s)
Vi is the initial velocity of the object (in our case 0 m/s because the object was at rest)
and t is the time it took to change from the Vi to the Vf (in our case 0.05 seconds.
Therefore we have:
Notice that the units of acceleration in the SI system are (meters divided square seconds)
Answer:
Angular acceleration, is
Explanation:
Given that,
Initial speed of the drill,
After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed,
We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.
So, the drill's angular acceleration is .