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Vesnalui [34]
3 years ago
7

The record time for a Tour de France cyclist to ascend the 1100-mm-high Alpe d'Huez is 37.5 minmin. The rider and his bike had a

mass of 65 kg. At the average speed of the ride, the metabolic power to ride on level ground would be 700 W. To this, we must add the power to make the climb. What was his total metabolic power?
Physics
1 answer:
katen-ka-za [31]3 years ago
7 0

Answer:

1945.6 W

Explanation:

We are given that

Height,h=1100 m

Time,t=37.5 min=37.5\times 60=2250 s

1 min=60 s

Mass,m=65 kg

Power,P=700 W

We have to find the his total metabolic power.

Power,=P'=\frac{W}{t}=\frac{mgh}{t}=\frac{65\times 9.8\times 1100}{2250}=311.4 W

Where g=9.8m/s^2

Efficiency =25%

Therefore,Power,P'=\frac{311.4}{0.25}=1245.6 W

Total metabolic power=P+P'=700+1245.6=1945.6 W

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The tire on this drag racer is severely twisted: The force of the road on the tire is quite large(most likely several times the
Andrew [12]

Answer: Speeding Up

Explanation:

Force is proportional to the acceleration of an object. The greater the force, the more acceleration will be produced.

When the force on the tire is equal to the weight of the car, the car is reaching a stability as a result of increase in motion.

But when the force of the load on the tire is quite large(most likely several times the weight of the car) and is directed forward, then, the car is at high speed.

4 0
3 years ago
A toroidal solenoid has an inner radius of 12.0 cm and an outer radius of 15.0 cm . It carries a current of 1.50 A . Part A How
tensa zangetsu [6.8K]

Answer:

The number of turns is  N  = 1750 \ turns

Explanation:

From the question we are told that

  The inner radius is r_i =  12.0 \  cm  =  0.12 \  m

   The outer radius is  r_o =  15.0 \  cm  =  0.15 \  m

   The current it carries is I =  1.50 \  A

    The magnetic field is  B  =   3.75 mT = 3.75 *10^{-3} \  T

   The distance from the center is d =  14.0 \ cm  =  0.14 \  m

Generally the number of turns is mathematically represented as

    N  =  \frac{2 *  \pi  * d  *  B}{ \mu_o *  r_o }

Generally  \mu_o is the permeability of free space with value  

    \mu_o  =  4\pi * 10^{-7} \ N/A^2

So

  N  =  \frac{2 *  3.142   * 0.14 *  3.75 *10^{-3} }{ 4\pi * 10^{-7}  * 0.15  }

  N  = 1750 \ turns

5 0
3 years ago
A compact car has a mass of 1380 kg . Assume that the car has one spring on each wheel, that the springs are identical, and that
astraxan [27]

Answer:

A) k=34867.3384\ N.m^{-1}

B) \omega'\approx84\ Hz

Explanation:

Given:

mass of car, m=1380\ kg

A)

frequency of spring oscillation, f=1.6\ Hz

We knkow the formula for spring oscillation frequency:

\omega=2\pi.f

\Rightarrow \sqrt{\frac{k_{eq}}{m} } =2\pi.f

\sqrt{\frac{k_{eq}}{1380} } =2\times \pi\times 1.6

k_{eq}=139469.3537\ N.m^{-1}

Now as we know that the springs are in parallel and their stiffness constant gets added up in parallel.

<u>So, the stiffness of each spring is (as they are identical):</u>

k=\frac{k_{eq}}{4}

k=\frac{139469.3537}{4}

k=34867.3384\ N.m^{-1}

B)

given that 4 passengers of mass 70 kg each are in the car, then the oscillation frequency:

\omega'=\sqrt{\frac{k_{eq}}{(m+70\times 4)} }

\omega'=\sqrt{\frac{139469.3537}{(1380+280)} }

\omega'\approx84\ Hz

7 0
3 years ago
Item 19 Question 1 A Ferris wheel has a radius of 75 feet. You board a car at the bottom of the Ferris wheel, which is 10 feet a
sergey [27]

Answer:

y = 104.4 ft

Explanation:

As we know that we board in the car of ferris wheel at the bottom position

So we will have

final height of the car at angular displacement given as

y = y_o + R + R sin(270 - 255)

y = y_o + R + R sin 15

here we know that

y_o = 10 ft

R = 75 ft

so we have

y = 10 + 75 + 75 sin15

y = 104.4 ft

4 0
3 years ago
How many protons are in this Atom if it has a balanced charge?
Dmitry [639]

Answer:

the answer is A

Explanation:

6 0
3 years ago
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