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Vesnalui [34]
3 years ago
7

The record time for a Tour de France cyclist to ascend the 1100-mm-high Alpe d'Huez is 37.5 minmin. The rider and his bike had a

mass of 65 kg. At the average speed of the ride, the metabolic power to ride on level ground would be 700 W. To this, we must add the power to make the climb. What was his total metabolic power?
Physics
1 answer:
katen-ka-za [31]3 years ago
7 0

Answer:

1945.6 W

Explanation:

We are given that

Height,h=1100 m

Time,t=37.5 min=37.5\times 60=2250 s

1 min=60 s

Mass,m=65 kg

Power,P=700 W

We have to find the his total metabolic power.

Power,=P'=\frac{W}{t}=\frac{mgh}{t}=\frac{65\times 9.8\times 1100}{2250}=311.4 W

Where g=9.8m/s^2

Efficiency =25%

Therefore,Power,P'=\frac{311.4}{0.25}=1245.6 W

Total metabolic power=P+P'=700+1245.6=1945.6 W

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Acceleration is found if we have the force and mass. 

With the following equation: F = ma, we can find the missing values. 

F = 25n
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Explanation:

We need to calculate the speed of light in each materials

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v=\dfrac{3\times10^{8}}{3.50}

v=8.6\times10^{7}\ m/s

(II) Carbon disulfide,

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v=\dfrac{3\times10^{8}}{1.63}

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v=\dfrac{3\times10^{8}}{1.50}

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A Ping-Pong ball with mass 2.5 g is attached by a thread to the bottom of a beaker. When the beaker is filled with water so that
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Answer:

0.022m or 2.2cm

Expxlanation:

Step 1:

Data obtained from the question. This includes:

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Acceleration due to gravity (g) = 9.81 m/s2

Diameter (d) =?

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Finding an expression to calculate the diameter of the ball. This is illustrated below:

Tension = weight displaced - weight of the ball

Weight displaced = Mass of water x acceleration due to gravity

Mass of water = Density x volume

Mass of water = ρxV

Weight displaced = ρxVxg = ρVg

Weight of the ball = Mass of the ball x acceleration due to gravity

Weight of the ball = mg

Therefore,

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T = ρVg - mg

Make V the subject of the formula

T = ρVg - mg

T + mg = ρVg

Divide both side by ρg

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Recall that the ball is spherical in shape and the Volume of a sphere is given by

V = 4/3πr^3

Radius (r) = diameter (d) /2

V = 4/3π(d/2)^3

V = 4/3πd^3/8

V = πd^3 /6

Substituting the value of V into equation 1, we have

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πd^3 /6 = ( T + mg) /ρg.

Making d the subject of the formula, we have:

πd^3 /6 = (T + mg) /ρg.

d^3 = 6(T + mg) /πρg.

Taking the cube root of both sides

d = [6(T + mg) /πρg]^1/3

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d = [6(0.029 + 2.5x10^-3x9.81)/ πx1000x9.81]^1/3

d = 0.022m

Therefore, the diameter of the ball is 0.022m or 2.2cm

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