Question

If i start with 32g s and 56 g fe, how many grams of product (fes) will i have? (assuming that all of the reactants are used up.)

Answer 1

If the reaction started with 32g of Sulfur and 56 grams of Iron, then mass of produced FeS is 88 grams.

What is the relation between mass & moles?

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

• W = given mass
• M = molar mass

Moles of Fe = 56g / 56g/mol = 1 mol

Moles of S = 32g / 32g/mol = 1 mol

Given chemical reaction is:

Fe + S → FeS

From the stoichiometry of the reaction same moles of iron and sulfur are required to produce equal moles of iron sulfide. Means 1 mole of iron produces 1 moles of iron sulfide and mass of iron sulfide will be calculated as:

W = (1mol)(88g/mol) = 88g

Hence required mass of iron sulfide is 88 grams.

To know more about mass & moles, visit the below link:
brainly.com/question/18983376

#SPJ1