If the reaction started with 32g of Sulfur and 56 grams of Iron, then mass of produced FeS is 88 grams.
<h3>What is the relation between mass & moles?</h3>
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
- W = given mass
- M = molar mass
Moles of Fe = 56g / 56g/mol = 1 mol
Moles of S = 32g / 32g/mol = 1 mol
Given chemical reaction is:
Fe + S → FeS
From the stoichiometry of the reaction same moles of iron and sulfur are required to produce equal moles of iron sulfide. Means 1 mole of iron produces 1 moles of iron sulfide and mass of iron sulfide will be calculated as:
W = (1mol)(88g/mol) = 88g
Hence required mass of iron sulfide is 88 grams.
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