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givi [52]
3 years ago
11

How does the number of atoms in one mole of argon compare with the number of molecules in one mole of ammonia

Chemistry
1 answer:
AfilCa [17]3 years ago
5 0
They are the same because the definition of a mole is 6.022 x 10^23 molecules or atoms based on whether it is a molecule or element. so there are 6.022 x 10^23 atoms of argon in one mole of argon and 6.022 x 10^23 molecules of ammonia in one mole of ammonia
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Suppose 2.4 g of Mg reacts with 10.0 g of O2, to create magnesium oxide. How much magnesium oxide is produced?
o-na [289]

Answer:

3.98 g

Explanation:

Step 1. Write the balanced chemical reaction. In this case, magnesium reacts with oxygen to produce magnesium oxide:

2~Mg(s) + O_2 (g)\rightarrow 2~MgO (s)

\\

Step 2. Calculate the number of moles of magnesium:

n_{Mg} = \frac{2.4~g}{24.305~g/mol} = 0.0987~mol

\\

Step 3. Calculate the number of moles of oxygen:

n_{O_2} = \frac{10.0~g}{32.00~g/mol} = 0.3125~mol

\\

Step 4. Identify the limiting reactant comparing the equivalents. Equivalent of Mg:

eq_{Mg} = \frac{0.0987~mol}{1} = 0.0987~mol

Equivalent of oxygen:

eq_{O_2} = \frac{0.3125~mol}{2} = 0.15625~mol

Therefore, Mg is the limiting reactant.

\\

Step 5. According to the stoichiometry of this reaction:

n_{Mg} = n_{MgO} = 0.0987~mol

\\

Step 6. Convert the number of moles of MgO into mass:

m_{MgO} = 0.0987~mol\cdot 40.304~g/mol = 3.98~g

5 0
3 years ago
The chemical formula for water is H202. True or <br> False
Goryan [66]

Answer:

False it is H2O

Explanation:

3 0
3 years ago
Read 2 more answers
A buffer is prepared by dissolving 0.80 moles of NH3 and 0.80 moles of NH4Cl in 1.00 L of aqueous solution. If 0.10 mol of NaOH
Vikki [24]

Answer:

a. 10.54

Explanation:

reaction is

NH₃ +  NaOH   -----------------NH₄Cl + H₂O

0.10 mol NaOH will consume 0.10 mol NH₃ thereby decreasing the initial amount of moles NH₃ and increasing that of NH₄Cl

mol NH₃  = 0.80 - 010 = .70

mol NH₄Cl = 0.80 + .10 = 0.90

pH = pKₐ + log (( NH₃/NH₄Cl))

pH =  9.26 + log (( 0.90 + 0.70)) = 9.26 + 0.11 = 10.54

7 0
2 years ago
Which reaction will occur? 2NaBr I2 Right arrow. 2NaI Br2 2Fe Al2O3 Right arrow. 2Al Fe2O3 2AgNO3 Ni Right arrow. Ni(NO3)2 2Ag P
Likurg_2 [28]

The reaction that has been occurred will be \rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3.

The chemical reaction has been defined as the interaction of the reactant  molecules for the formation of the product. The changes have been taken place in the reactivity series and under specific conditions.

<h3>Reaction occur</h3>

The displacement reaction has been taken place based on the reactivity series. The more reactive element has been able to displace the less reactive element in the compound and form a new compound.

The following reactions have been analyzed as:

  • \rm 2\;NaBr\;+\;I_2\;\rightarrow\;2\;NaI\;+\;Br_2

In the reaction, Br has been replaced by Iodine. The iodine has been less reactive than Br and thus will not form the compound.

Thus, this reaction will not occur.

  • \rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3

In the reaction, Al has been replaced by Fe. The Fe is more reactive than Al. thus this reaction will occur.

  • \rm 2\;AgNO_3\;+\;Ni\;\rightarrow\;Ni(NO_3)_2\;+\;2\;Ag

The nickel has been less reactive than Ag, and thus will not be able to form the product.

Thus, this reaction will not occur.

  • \rm Pb\;+\;Zn(C_2H_3O_2)_2\;\rightarrow\;Zn\;+\;Pb(C_2H_3O_2)_2

The lead has been less reactive than Zn, and thus will not be able to form the product.

Thus, this reaction will not occur.

The reaction that has been occurred will be \rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3.

Learn more about reactivity series, here:

brainly.com/question/10443908

8 0
2 years ago
how many calories of energy are given off to lower the temperature of 100.0g of iron from 150.0°C to 35.0°C?
jeyben [28]

Answer:

ΔT = Tfinal − Tinitial = 150°C − 35.0°C = 125°C

given the specific heat of iron as 0.108 cal/g·°C

heat=(100.0 g)(0.108 cal /g· °C )(125°C) =

  100x 0.108x125= 1350 cal

4 0
3 years ago
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