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givi [52]
3 years ago
11

How does the number of atoms in one mole of argon compare with the number of molecules in one mole of ammonia

Chemistry
1 answer:
AfilCa [17]3 years ago
5 0
They are the same because the definition of a mole is 6.022 x 10^23 molecules or atoms based on whether it is a molecule or element. so there are 6.022 x 10^23 atoms of argon in one mole of argon and 6.022 x 10^23 molecules of ammonia in one mole of ammonia
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Answer:

0.40 L

Explanation:

Calculation of the moles of Ba(OH)_2 as:-

Mass = 51.24 g

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The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{51.24\ g}{171.34\ g/mol}

Moles= 0.2991\ mol

Volume = 1.20 L

The expression for the molarity is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.2991\ mol}{1.20\ L}=0.24925\ M

Thus,

Considering

Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}

Given  that:

Molarity_{working\ solution}=0.100\ M

Volume_{working\ solution}=1\ L

Volume_{stock\ solution}=?

Molarity_{stock\ solution}=0.24925\ M

So,  

0.100\ M\times 1\ L=0.24925\ M\times Volume_{stock\ solution}

Volume_{stock\ solution}=\frac{0.100\times 1}{0.24925}\ L=0.40\ L

<u>The volume of 0.24925M stock solution added = 0.40 L </u>

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