The rate of change of (g)=0.024M/s when the rate of change of is – 0.012 M/s.
<h3>What is the rate of reaction?</h3>
Reaction rate, in chemistry, is the speed at which a chemical reaction proceeds.
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Rate = \frac{-dcs_2}{dt} =\frac{-do_2}{dt} =\frac{+dco_2}{dt} =\frac{1dso_2}{dt}
Given:
The rate of change of (g)=0.024M/s
Hence, the rate of change of (g)=0.024M/s
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Molality is defined as the number of moles of solute in 1 kg of solvent.
In this case the solvent is water, therefore we need to find the number of moles of KBr in 1 kg of water.
Number of moles of KBr - 2.10 g / 119 g/mol = 0.0176 mol
mass of water - 897 g
number of moles of KBr in 897 g - 0.0176 mol
Therefore number of KBr moles in 1000 g - 0.0176 mol / 897 g x 1000 g = 0.0196 mol/kg
therefore molality of KBr is 0.0196 mol/kg
Yes you are right .. X is undergoing a change from solid to gas at point E
Answer:
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A. Strong Acid vs. Strong Base