What is the temperature of 0,80 mol of a gas stored in a 275 mL cylinder at 175 kPa?
1 answer:
Answer:
First, let's express pressure P in Pa and volume V in m3:
⇒P=175 kPa
⇒P=1.75×105 Pa
and
⇒V=275 ml
⇒V=2.75×10−4 m3
Then, let's solve the ideal gas law PV=nRT for temperature T:
⇒PV=nRT
⇒T=PVnR
Substituting the appropriate values into the equation:
⇒T=1.75×105×2.75×10−40.80×8.314 K
⇒T=48.1256.6512 K
∴T≈7.24 K
Therefore, the temperature is around 7.24 K.
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