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Lady_Fox [76]
2 years ago
7

The environmental Protection Agency (EPA) has two programs that make a business an energy star. They are the following:

Engineering
1 answer:
valkas [14]2 years ago
7 0

The environmental Protection Agency (EPA) has two programs that make a business an energy star which are Energy Star program and WaterSense.

<h3>What is environmental Protection Agency (EPA)?</h3>

This is an agency in the United States, designed to enforce regulations that protect the environment and natural resources.

The Agency does the following :

  1. Protects people and the environment from significant health risks.
  2. Sponsors and conducts research.
  3. Develop ideas towards protecting the environment.

Hence, the environmental Protection Agency (EPA) has two programs that make a business an energy star which are Energy Star program and WaterSense.

Learn more about environmental Protection Agency (EPA) here :  brainly.com/question/20299710

#SPJ1

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A large spherical tank contains gas at a pressure of 400 psi. The tank is constructed of high-strength steel having a yield stre
jok3333 [9.3K]

Answer:

t=2.025 inches

Explanation:

Given that

P = 400 Psi

Yield stress ,σ = 80 ksi

Diameter ,d= 45 ft

We know that

1 ft = 12 inches

d= 540 inches

Factor of safety ,K= 3

The required thickness given as

\dfrac {Pd}{4t}=\dfrac{\sigma}{K}

t=thickness

\dfrac {PdK}{4\sigma}=t

\dfrac {400\times 540\times 3}{4\times 80\times 1000}=t

t=2.025 inches

Therefore thickness will be 2.025 inches.

5 0
3 years ago
What are the potential hazards relating to materials handling injuries?
Ann [662]

Answer:

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8 0
3 years ago
The crash rate per mile is.
Colt1911 [192]

Answer:

75 percent

Explanation:

8 0
3 years ago
Balanced forces will result in which of the following
tia_tia [17]
D is the answer. Hope this helped
8 0
3 years ago
Your Java program will be reading input from a file name strInput.txt. Each record contains String firstname String lastName Str
stiks02 [169]

Answer:

The program requires that you have the specified input files and it reads from each file at a time and processes salary in digits, states the city, state and bonus with respective first and last name as requested in the question. Note that you must have access to the mentioned output files for the program to work properly. Below is the java version of the program.

import java.io.File;

import java.io.FileNotFoundException;

import java.io.PrintWriter;

import java.util.Scanner;

class Driver

{

public static void main(String[] args) throws FileNotFoundException

{

Scanner sc = new Scanner(new File("strInput.txt"));

PrintWriter pd = new PrintWriter(new File("strOutputD"));

PrintWriter prf = new PrintWriter(new File("strOutputRF"));

String firstname = "", lastname = "", strSalary = "", status = "", cityState = "", city = "", state = "";

double salary = 0, bonus = 0;

int incorrectRecords = 0;

int dRecords = 0;

int fRecords = 0;

while(sc.hasNextLine())

{

firstname = sc.next();

lastname = sc.next();

strSalary = sc.next();

status = sc.next();

cityState = sc.next();

if(!status.equals("D") && !status.equals("F"))

{

System.out.println("Records is neither D nor F. Skipping this...");

incorrectRecords++;

continue;

}

else if(status.equals("D") || status.equals("F"))

{

char c = ' ';

int i = 0;

for(i=0; i<strSalary.length() && c != '.'; i++)

{

c = strSalary.charAt(i);

if(!Character.isDigit(c))

{

System.out.println("Char at position " + (i+1) + " in salary is not a digit");

incorrectRecords++;

continue;

}

}

if(c == '.')

{

if(i+1 == strSalary.length()-1)

{

if(!Character.isDigit(strSalary.charAt(i)))

{

System.out.println("Char at position " + (i+1) + " in salary is not a digit");

incorrectRecords++;

continue;

}

if(!Character.isDigit(strSalary.charAt(i+1)))

{

System.out.println("Char at position " + (i+1+1) + " in salary is not a digit");

incorrectRecords++;

continue;

}

}

else

{

System.out.println("Period is in the wrong position. Expected at " + (strSalary.length()-3) + " but found at " + (i+1));

continue;

}

}

city = cityState.split(",")[0];

state = cityState.split(",")[1];

salary = Double.parseDouble(strSalary);

if(status.equals("D"))

{

bonus = salary * 0.125;

dRecords++;

pd.write(firstname + " " + lastname + " " + status + " " + salary + " " + bonus + " " + city + " " + state);

}

else

{

bonus = salary * 0.18;

fRecords++;

prf.write(firstname + " " + lastname + " " + status + " " + salary + " " + bonus + " " + city + " " + state);

}

}

}

System.out.println("No of D records : " + dRecords);

System.out.println("No of F records : " + fRecords);

System.out.println("No of incorrect records : " + incorrectRecords);

}

}

6 0
3 years ago
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