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Naya [18.7K]
2 years ago
14

Which type of reaction is shown?

Chemistry
1 answer:
Alina [70]2 years ago
4 0

According to the image in this question, the type of reaction shown is that of fission because nuclei are being split into smaller and smaller places.

<h3>What is nuclear fission?</h3>

Nuclear fission in radioactivity is the process whereby the nuclei of atoms split into smaller particles.

In the above diagram, an atom of uranium is labeled and its nucleus is shown to split into smaller particles in succession.

Therefore, the reaction exemplifies a nuclear fission because nuclei are being split into smaller and smaller places.

Learn more about fission at: brainly.com/question/2732120

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Explanation:

I suggest looking at the electron configuration chart, it has really helped me a lot :)

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¿Cuáles son las formas alotrópicas del carbono (como se encuentra en la naturaleza)?
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Explanation:

3 0
3 years ago
Compare and contrast solids liquids and gases in terms of volume shape compessibility and energy
tangare [24]

Answer:

solid has definite shape and volume.

liquid do not have definite shape but have definite volume.

gas do not have definite shape and definite volume.

solid have lowest compressibility out of three, liquid have more compressibility than solid but less than gases. gases have the highest compressibility out of three. Molecules in the solid phase have the least amount of energy, while gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles.

8 0
3 years ago
Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1
kari74 [83]

Answer:

\boxed {\boxed {\sf 56 \ Joules}}

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

q=mc \Delta T

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 95°C - 15°C = 80°C

We know the variables and can substitute them into the formula.

m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C

q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)

Multiply the first numbers. The grams will cancel.

q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )

Multiply again. This time the degrees Celsius cancel.

q= 56 \ J

56 Joules of heat are needed.

4 0
3 years ago
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