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Naya [18.7K]
3 years ago
14

Which type of reaction is shown?

Chemistry
1 answer:
Alina [70]3 years ago
4 0

According to the image in this question, the type of reaction shown is that of fission because nuclei are being split into smaller and smaller places.

<h3>What is nuclear fission?</h3>

Nuclear fission in radioactivity is the process whereby the nuclei of atoms split into smaller particles.

In the above diagram, an atom of uranium is labeled and its nucleus is shown to split into smaller particles in succession.

Therefore, the reaction exemplifies a nuclear fission because nuclei are being split into smaller and smaller places.

Learn more about fission at: brainly.com/question/2732120

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Naddik [55]

Answer:

Mechnical weathering

Explanation:

5 0
3 years ago
Read 2 more answers
What is the purpose of balancing chemical reactions?
Karo-lina-s [1.5K]

Answer: I believe its 1

Hope this helps!

4 0
2 years ago
ILL MARK BRAINLIEST :)
DanielleElmas [232]

Explanation:

According to the law of conservation of mass, mass can neither be created nor destroyed but it can simply be transformed from one form to another.

For example, Na^{+} + Cl^{-} \rightarrow NaCl

Mass of Na = 23 g/mol

Mass of Cl = 35.5 g/mol

Sum of mass of reactants = mass of Na + mass of Cl

= 23 + 35.5 g/mol

= 58.5 g/mol

Mass of product formed is as follows.

Mass of NaCl = mass of Na + mass of Cl

= (23 g/mol + 35.5) g/mol

= 58.5 g/mol

As mass reacted is equal to the amount of mass formed. This shows that mass is conserved.

As a result, law of conservation of mass is obeyed.

3 0
3 years ago
How much heat (kj) is required to convert 3.12 moles of liquid benzene at 75.1°c to gaseous benzene at 115.1°c?
Tems11 [23]
The total energy includes sensible heat to raise the temperature from 75.1°C to the boiling point. It also includes the latent heat to convert the liquid to gas. Then, it also includes sensible heat from he boiling point to 115.1°C. The equation is:

Energy = nCp,liquid(T,bp - T₁) + nΔH + nCp,gas(T₂ - T,bp)
where
n is the number of moles
T,bp is the boiling point of benzene at 80.1°C
Cp,liquid = 134.8 J/mol·°C
Cp,gas = 82.44 J/mol·°C
ΔH = 87.1 J/mol

Energy = (3.12 moles)(134.8 J/mol·°C)(80.1°C - 75.1°C) + (3.12 moles)(87.1 J/mol) + (3.12 moles)(82.44 J/mol·°C)(115.1°C - 80.1°C)
Energy = 11,377.08 J
3 0
3 years ago
What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273 K under 75 kPa?
Zina [86]
Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure

Use the ideal gas law, given by
pV=nRT \\ or \\  V= \frac{nRT}{p}
where
V = volume
R = 8.3145 J/(mol-K), the gas constant

Therefore,
V= \frac{(12\,mol)(8.3145\, \frac{J}{mol-K} )(273\,K)}{75 \times 10^{3} \, Pa}= 0.3632\,m^{3}

Answer: 0.363 m³
    
5 0
4 years ago
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