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Rus_ich [418]
3 years ago
13

A small, rigid object carries positive and negative 3.00 nC charges. It is oriented so that the positive charge has coordinates

(−1.20 mm, 1.20 mm) and the negative charge is at the point (1.70 mm, −1.30 mm).
Required:
a. Find the electric dipole moment of the object.
b. The object is placed in an electric field E = (7.80 103 î − 4.90 103 ĵ). Find the torque acting on the object.
c. Find the potential energy of the object–field system when the object is in this orientation.
d. Assuming the orientation of the object can change, find the difference between the maximum and the minimum potential energies of the system,

Physics
1 answer:
enot [183]3 years ago
8 0

Answer:

Umax = 105.8nJ

Umin =-105.8nJ

Umax-Umin = 211.6nJ

Explanation:

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Two auto technicians are discussing the stages of engine operation. Auto Technician A says during the intake stage of engine ope
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An engineer weighs a sample of mercury (ρ = 13.6 × 103 kg/m3 ) and finds that the weight of the sample is 6.0 n. what is the sam
Amanda [17]
Given:
ρ = 13.6 x 10³ kg/m³, density of mercury
W = 6.0 N, weight of the mercury sample
g = 9.81 m/s², acceleration due to gravity.

Let V =  the volume of the sample.
Then
W = ρVg
or
V =  W/(ρg)
   = (6.0 N)/[(13.6 x 10³ kg/m³)*(9.81 m/s²)]
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5 0
3 years ago
A car traveling at 43 km/h hits a bridge abutment. A passenger in the car moves forward a distance of 54 cm (with respect to the
Brums [2.3K]

Answer:

F = -6472.9 N

F= -6.47 kN

Explanation:

First of all you have to convert the data to SI  units

so for the velocity you have :

Vi = 43km/h *(1000m/1km)*(1h/3600s)  ---> using conversion factors

Vi= 11.9444 m/s

dX : distance the passanger moves

dX = 54cm*(1m/100cm)   -->  using conversion factors

dX = 0.54 m

Now to calculate the force we are going to use the sum of focers equals to mass for acceleration:

Sum F = m*a

We have to find a so we are going to use the velocity's formula as follows to solve a:

Vf ^2 = Vi^2 +2*a*dX

Vf=0  --> the passenger does not move after the airbag inflates.

a= -(Vi^2)/(2*dX)

you solve de acceleration with the data you hae and you will find

a = -132.1 m/ s^2

Now you can solve the Sum F equation

Sum F = 49 Kg * (-132.1 m/s^2)

F = -6472.9 N

F= -6.47 kN

6 0
3 years ago
Express 75−−√ in the form ab√.
Nana76 [90]
We can write 75 = 25 x 3
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Now we know that square root of 25 is 5 a 5x5 = 25 
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8 0
3 years ago
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