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3 years ago

11

WHAT IS A TOROID IN HYDRAULUCS?

2 answers:

slamgirl [31]3 years ago

8 0

Answer:

Expl

A hydraulic actuator comprised of a toroidal piston within a toroidal enclosure, with differential fluid pressure alternatively applied to upper and lower surfaces of the piston to cause a reciprocating motion, and with plural double ended piston rods extending in parallel above and below the piston, and slidably extending in fluid sealed relation through end caps of the toroidal enclosure to distribute the vibrational force produced by the reciprocating piston over plural points of a surface area of the mass to be vibrated, thereby reducing the likelihood of stress, strain, or harmonics in the mass.anation:

xenn [34]3 years ago

3 0

Answer:

A hydraulic actuator comprised of a toroidal piston within a toroidal enclosure, with differential fluid pressure alternatively applied to upper and lower surfaces of the piston to cause a reciprocating motion, and with plural double ended piston rods extending in parallel above and below the piston, and slidably extending in fluid sealed relation through end caps of the toroidal enclosure to distribute the vibrational force produced by the reciprocating piston over plural points of a surface area of the mass to be vibrated, thereby reducing the likelihood of stress, strain, or harmonics in the mass.

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Given the latent heat of fusion (melting) and the latent heat of vaporisation for water are Δhs = 333.2 kJ/kg and Δhv = 2257 kJ/

kap26 [50]

Answer:

C)185,500 KJ

Explanation:

Given that

Latent heat fusion = 333.23 KJ/kg

Latent heat vaporisation = 333.23 KJ/kg

Mass of ice = 100 kg

Mass of water = 40 kg

Mass of vapor=60 kg

Ice at 0°C ,first it will take latent heat of vaporisation and remain at constant temperature 0°C and it will convert in to water.After this water which at 0°C will take sensible heat and gets heat up to 100°C.After that at 100°C vapor will take heat as heat of vaporisation .

Sensible heat for water Q

$Q=mC_p\Delta T$

For water

$C_p=4.178\ KJ/Kg.K$

Q=4.178 x 40 x 100 KJ

Q=16,712 KJ

So total heat

Total heat =100 x 333.23+16,712 + 60 x 2257 KJ

Total heat =185,455 KJ

Approx Total heat = 185,500 KJ

So the answer C is correct.

8 0

4 years ago

Consider an open loop 1-degree-of-freedom mass-spring damper system. The system has mass 4.2 kg, and spring stiffness of 85.9 N/

Marat540 [252]

Answer:

Damping ratio $\zeta =0.0342$

Explanation:

Given that

m=4.2 kg,K=85.9 N/m,C=1.3 N.s/m

We need to find damping ratio

We know that critical damping co-efficient

$C_c=2\sqrt {mk}$

$C_c=2\sqrt {4.2\times 85.9}$

$C_c=37.98$ N.s/m

Damping ratio( $\zeta$ ) is the ratio of damping co-efficient to the critical damping co-efficient

So $\zeta =\dfrac{C}{C_c}$

$\zeta =\dfrac{1.3}{37.98}$

$\zeta =0.0342$

So damping ratio $\zeta =0.0342$

3 0

4 years ago

A treatment plant being designed for Cynusoidal City requires an equalization basin to even out flow and BOD variations. The ave

sineoko [7]

Answer:

The size of equalization basin is 6105.6 m³

Explanation:

The average flow is:

flow = ∑flow/n = 9.788/24 = 0.408 m³/s

Where n is the number or observations.

The inflow volume is:

$V_{inflow} =Q*t$

where t is the time interval

$V_{inflow} =0.446(1*3600)=1605m^{3}$

in the same way it is calculated the inflow volume for each observation

The outflow volume is:

$V_{out} =Q_{out} *t=0.4*(1*3600)=1400m^{3}$

The volume of flow is:

$ds=V_{inflow} -V_{out} =1605-1400=205m^{3}$

in the same way it is calculated the volume of flow for each observation. According to the file attach, the highest volume is 6105.6 m³

6 0

3 years ago

Calculate the frequencies (in Hz) for the ten lowest modes of a rigid-wall room of dimensions 2.59m x 2.42m x 2.82m (i.e., find

Digiron [165]

Answer:

For This Answer Please See the Attached File.

Explanation:

3 0

3 years ago

What is the saturation pressure, Vf, and Vg for saturated water at a temperature of 287 °C?

Dvinal [7]

Answer:

Vf = specific volume of saturated liquid = 0.0217158 ft^3/lb

Vg = specific volume of saturated steam = 0.430129 ft^3/lb

Explanation:

Given data:

water temperature is given as 287-degree Celcius

we have to find Vf and Vg

Vf = specific volume of saturated liquid

Vg = specific volume of saturated steam

we know that from the saturated steam table we can find these value

therefore for temperature 287-degree Celcius

Vf = specific volume of saturated liquid = 0.0217158 ft^3/lb

Vg = specific volume of saturated steam = 0.430129 ft^3/lb

6 0

3 years ago