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1 year ago

Introduction to forces

Physics

1 answer:

ELEN [110]1 year ago

8 0

Answer: Force

A push, pull or twist that can change an object's position, direction, speed or shape.

Explanation:

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Please help

inysia [295]

Explanation:

Start with what you know and list your knowns and unknowns

F = ma

F= 3N

m = 6kg

a =?

3N = 6kg x a

solve for a

3N / 6kg = a

3 0

3 years ago

An ant clings to the outside edge of the tire of an exercise bicycle. When you start pedaling, the ant's speed increases from ze

konstantin123 [22]

Answer:

1- 3.64 m/s

2- 0.28 m

3- 70.8 rad

4- 19.8 m

Explanation:

see attachment

3 0

2 years ago

A uniform disk of mass M = 4.9 kg has a radius of 0.12 m and is pivoted so that it rotates freely about its axis. A string wrapp

AlekseyPX

Answer:

(A) 2.4 N-m

(B) $0.035kgm^2$

(D) 1741.13 J

(E) 725.481 rad

Explanation:

We have given mass of the disk m = 4.9 kg

Radius r = 0.12 m, that is distance = 0.12 m

Force F = 20 N

(a) Torque is equal to product of force and distance

So torque $\tau =Fr$ , here F is force and r is distance

So $\tau =20\times 0.12=2.4Nm$

(B) Moment of inertia is equal to $I=\frac{1}{2}mr^2$

So $I=\frac{1}{2}\times 4.9\times 0.12^2=0.035kgm^2$

Torque is equal to $\tau =I\alpha$

So angular acceleration $\alpha =\frac{\tau }{I}=\frac{2.4}{0.035}=68.571rad/sec^2$

So initial angular speed $\omega _{0}=0rad/sec$

Time t = 4.6 sec

From first equation of motion we know that $\omega =\omega _0+\alpha t$

So $\omega =0+68.571\times 4.6=315.426rad/sec$

(D) Kinetic energy is equal to $KE=\frac{1}{2}I\omega ^2=\frac{1}{2}\times 0.035\times 315.426^2=1741.13J$

(E) From second equation of motion

$\Theta =\omega _0t+\frac{1}{2}\alpha t^2=0\times 4.6+\frac{1}{2}\times 68.571\times 4.6^2=725.481rad$

3 0

3 years ago

Imagine the ball on the left is given a nonzero initial speed in the horizontal direction, while the ball on the right continues

Llana [10]

Let say the height of two balls from the ground is H

now we can use kinematics

$s = v_i * t + \frac{1}{2} at^2$

now we have

$H = \frac{1}{2}gt^2$

$t = \sqrt{\frac{2H}{g}}$

now in the same time ball on the left will cover the horizontal distance between them

$v_x = \frac{d}{ t}[/tex[tex]v_x = \frac{3}{\sqrt{\frac{2H}{g}}}$

<em>so above is the horizontal speed of the left ball</em>

8 0

3 years ago

Light travels faster in a material with a lower index of refraction.

lidiya [134]

Answer:true

Explanation:

The lower the refractive index,the faster the velocity of light

4 0

3 years ago

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