Ask question

Ask question

All categories

2 years ago

9

Help me please on this

1 answer:

Norma-Jean [14]2 years ago

6 0

So what u do is 2112393921010

You might be interested in

A charge of -3.40 nC is placed at the origin of an xy-coordinate system, and a charge of 2.45 nC is placed on the y axis at y =

gavmur [86]

Answer:

The magnitude of this force is $1.866\times10^{-4}\ N$

The direction of this force is 55.69°.

Explanation:

Given that,

Charge at origin $q_{1}= -3.40\ nC$

Charge at y axis $q_{2}= 2.45\ nC$

Distance on y axis = 4.25 cm

Third charge $q_{3}= 5.00\ nC$

Distance on x axis = 2.90 cm

(a). We need to calculate the force F₁₃

Using formula of force

$F_{13}=\dfrac{kq_{1}q_{3}}{r^2}$

Put the value into the formula

$F_{13}=\dfrac{9\times10^{9}\times(-3.40\times10^{-9})\times5.00\times10^{-9}}{(2.90\times10^{-2})^2}$

$F_{13}=-0.00018192\ N$

$F_{13}=-1.82\times10^{-4}\ N$

We need to calculate the force F₁₂

Using formula of force

$F_{12}=\dfrac{kq_{1}q_{2}}{r^2}$

Put the value into the formula

$F_{12}=\dfrac{9\times10^{9}\times(-3.40\times10^{-9})\times2.45\times10^{-9}}{(4.25\times10^{-2})^2}$

$F_{12}=-0.00004150\ N$

$F_{12}=-4.15\times10^{-5}\ N$

The magnitude of this force is

The total force exerted on this charge by the other two charges.

$F=\sqrt{F_{13}^2+F_{12}^2+2F_{13}F_{12}\cos \theta}$

Here, $\theta=90$

$F=\sqrt{F_{13}^2+F_{12}^2}$

Put the value into the formula

$F=\sqrt{(-1.82\times10^{-4})^2+(-4.15\times10^{-5})^2}$

$F=0.0001866\ N$

$F=1.866\times10^{-4}\ N$

(c). We need to calculate the direction of this force

Using formula of direction

$\tan\theta=\dfrac{y}{x}$

Put the value into the formula

$\theta=\tan^{-1}(\dfrac{4.25}{2.90})$

$\theta=55.69^{\circ}$

Hence, The magnitude of this force is $1.866\times10^{-4}\ N$

The direction of this force is 55.69°.

3 0

4 years ago

a horizontal force of 2500 N is applied for a time of 30 seconds to the car mass of 1000 kg if the car is at rest and friction i

Digiron [165]

Newton’s second law: F=ma. 2500=1000a. a=2.5m/s*s. Final velocity is 2.5*30=75m/s. Average speed is (Vi+Vf)/2, which is 37.5m/s. D=vt. 37.5*30=1125m. The distance traveled is 1125 meters

6 0

4 years ago

Which has more potential energy: an eraser 2 feet above your head or a brick 2 feet above your head?

Vika [28.1K]

The brick because it has more mass which means more potential energy

3 0

3 years ago

What should you do if you need to pull over to get some rest?

Zielflug [23.3K]

Pull into the lot of a place that's 24 hours therefor if a office drives by its just a car

3 0

3 years ago

PLEASE HELPPPPPP <333

True [87]

Answer:

the answer is b

Explanation:

gravity pulls you down so on a scale you will weigh more. less gravity you will weigh less.

8 0

3 years ago