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julia-pushkina [17]
1 year ago
12

Do you agree that heat can do work by constructing a model? Explain

Chemistry
1 answer:
ValentinkaMS [17]1 year ago
8 0

Work can be totally transformed into heat (for example, by friction), whereas heat can only be partially converted into work.

<h3>What is a model?</h3>

A model is a depiction of something that is frequently too difficult to directly observe or display. Although experimental testing validates a model, it is only accurate in explaining specific characteristics of a physical system.

Work is defined as the transfer of energy to or from a system by any means other than heat.

A transfer of energy to or from a system by any means other than heat is called “work”. Work can be completely converted into heat (by friction, for example), but heat can only be partially converted to work. The Second Law of Thermodynamics, states that the complete conversion of heat into work is impossible.

Heat transmission in materials can be described using the kinetic particle model. Heat energy always travels from a high-temperature zone to a low-temperature region.

Thus, heat can do work by constructing a model.

To learn more details about heat here:

brainly.com/question/1429452

#SPJ1

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All the elements of a family in the periodic table have what feature in common?
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They all have the same number of electrons in the electron cloud.

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4 0
3 years ago
A mixture of XO2 (P = 3.00 atm) and O2 (P = 1.00 atm) is placed in a container. This elementary reaction takes place at 27 °C: 2
sukhopar [10]

Answer:

a) \triangle G^{0} = 7.31 kJ/mol

b) K_{-1} = 0.0594 m^{-1} s^{-1}

Explanation:

Equation of reaction:

                                     2 XO_{2} (g) + O_{2} (g) \rightleftharpoons 2XO_{3} (g)

Initial pressure                  3              1              0

Pressure change             2P           1P             2P

Total pressure = (3-2P) + (1-P) + (2P)

Total Pressure = 3.75 atm

(3-2P) + (1-P) + (2P) = 3.75

4 - P = 3.75

P = 4 - 3.75

P = 0.25 atm

Let us calculate the pressure of each of the components of the reaction:

Pressure of XO2 = 3 - 2P = 3 - 2(0.25)

Pressure of XO2 =2.5 atm

Pressure of O2 = 1 - P = 1 -0.25

Pressure of O2 = 0.75 atm

Pressure of XO3 = 2P = 2 * 0.25

Pressure of XO3 = 0.5 atm

From the reaction, equilibrium constant can be calculated using the formula:

K_{p} = \frac{[PXO_{3}] ^{2} }{[PXO_{2}] ^{2}[PO_{2}] }

K_{p} = \frac{0.5^2}{2.5^2 *0.75} \\K_{p} = 0.0533 = K_{eq}

Standard free energy:

\triangle G^{0} = - RT ln k_{eq} \\\triangle G^{0} = -(0.008314*300* ln0.0533)\\\triangle G^{0} = 7.31 kJ/mol

b) value of k−1 at 27 °C, i.e. 300K

K_{1} = 7.8 * 10^{-2} m^{-2} s^{-1}

K_{c} = K_{p}RT\\K_{c} = 0.0533* 0.0821 * 300\\K_{c} = 1.313 m^{-1}

K_{-1} = \frac{K_{1} }{K_{c} } \\K_{-1} = \frac{7.8 * 10^{-2}  }{1.313 }\\K_{-1} = 0.0594 m^{-1} s^{-1}

6 0
3 years ago
A beaker contains a mixture of sand and small pebbles. what kind of mixture is this?
melomori [17]
Answer is: a beaker contains <span>heterogeneous mixture.

</span>

A heterogeneous mixture<span> have compounds that remain separate in the sample.</span>

Heterogeneous mixture is not uniform in composition (in this mixture different sand and small pebbles), but proportions of its components (in this mixture particles of different colors and size) vary throughout the sample.

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