Answer:
Explanation:
Given that
F=2x³
Work is given as
The range of x is from x=0 to x=D
W=-∫f(x)dx
Then,
W=-∫2x³dx from x=0 to x=D
W=- 2x⁴/4 from x=0 to x=D
W=-2(D⁴/4-0/4)
W=-D⁴/2
W=1/2D⁴
The correct answer is F
The ion of idodine is neutral
Explanation:
Given that,
Initial speed of the object, u = 1 m/s
Acceleration of the object, 
We need to find the time when the object comes at rest (v=0). Let it is given by :
t = 1 second
So, the object will comes to rest at 1 second. Hence, this is the required solution.
F=G(m1*m2)\D^2
so
G=6.67 × 10^(-11)<span> m</span>3<span> kg</span>-1<span> s</span><span>-2
</span>
= G(2*2)\4
=G
Answer:
v = 2 cm/s
Explanation:
The equation of the wave is
y(x,t) = (2.0cm)*cos(2π*x−4π*t)
Where,
x is measured in cm
t in s
A more general formula for this equation would be
y(x,t) = A*cos(k*x−ω*t)
Where,
A = amplitude.
k = the wavenumber
ω = the angular frequency
The velocity of the wave corresponds to
v = ω/k
v = 4π / 2π = 2 cm/s
v = 2 cm/s
