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Alexeev081 [22]
2 years ago
15

Given the [H+] = 3.89x10^-7M, what is the pOH?

Chemistry
1 answer:
Orlov [11]2 years ago
7 0

Answer:

7.59

Explanation:

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Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these
deff fn [24]
The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,

     N₂ + H₂ + 3O₂ --> 2HNO₃

The net enthalpy of formation of nitric acid is calculated by,
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Since all the reactants are in their elemental forms, the simplified equation would be,

    Hrxn = Hproduct 

Substituting,

    Hrxn = (-186.81 kJ/mol)(2 mols)

<em>Answer: -372.42 kJ</em>

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3 years ago
Is it possible for the equivalence point of a titration to not be at pH 7? Explain your answer.
lara31 [8.8K]
<span>The reason it will be 7 for some titrations is that when you  titrates a strong acid with a strong base for example  HCl and NaOH the salt formed is conjugate base of strong acid and will be a very weak base
 That means that it cannot produce any OH^-1 and all the H+ has been converted to water.The only source of H+ or OH is water with a Ka of 10^-14 so the pH = -log [H+]=-log 10^-7 = 7 
second reason is 
When you titrates a weak acid with strong base at equivalence point 
only a water solution of the conjugate base exists 

CH3COOH + NaOH ----- Na+ CH3COO^-1 + H2O 
Since the conjugate base is the conjugate base of a weak acid it will hydrolyze in water like so 
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3 years ago
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Electric current produces a magnetic field. This magnetic field can be visualized as a pattern of circular field lines surrounding a wire. One way to explore the direction of a magnetic field is with a compass, as shown by a long straight current-carrying wire in.

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To get a 4 suggest a way to improve the accuracy or precision of the finding<br> .
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3 years ago
A student collects 450. mL of HCl gas at a pressure of 101 kPa and a temperature of 17ºC. What would the volume of the gas be if
xenn [34]

Answer:

449 mL

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 450 mL

V₂ = ?

P₁ = 101 kPa

P₂ = 104 kPa

T₁ = 17 ºC

T₂ = 25 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (17 + 273.15) K = 290.15 K

T₂ = (25 + 273.15) K = 298.15 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{101}\times {450}}{290.15}=\frac {{104}\times {V_2}}{298.15}

Solving for V₂ , we get:

V₂ = 449 mL

8 0
3 years ago
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