The velocity of the ball when it strikes the ground, given the data is 21.56 m/s
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Time to reach ground from maximum height (t) = 2.2 s
- Initial velocity (u) = 0 m/s
- Acceleration due to gravity (g) = 9.8 m/s²
- Final velocity (v) =?
<h3>How to determine the velocity when the ball strikes the ground</h3>
The velocity of the ball when it strikes the ground can be obtained as illustrated below:
v = u + gt
v = 0 + (9.8 × 2.2)
v = 0 + 21.56
v = 21.56 m/s
Thus, the velocity of the ball when it strikes the ground is 21.56 m/s
Learn more about motion under gravity:
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Answer:
The correct one is that the force on B is half of the force on A
Explanation:
Because radius for the inside of the curve is half the radius for the outside and Car A travels on the inside while car B, travels at equal speed on the outside of the curve. Thus force on B will be half on A
Answer:
Average density of Sun is 1.3927 
.
Given:
Radius of Sun = 7.001 ×
km = 7.001 ×
cm
Mass of Sun = 2 × 
kg = 2 × 
g
To find:
Average density of Sun = ?
Formula used:
Density of Sun = 
Solution:
Density of Sun is given by,
Density of Sun =
Volume of Sun = 
Volume of Sun = ![\frac{4}{3} \times 3.14 \times [7.001 \times 10^{10}]^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%20%5Ctimes%203.14%20%5Ctimes%20%5B7.001%20%5Ctimes%2010%5E%7B10%7D%5D%5E%7B3%7D)
Volume of Sun = 1.436 × 
Density of Sun = 
Density of Sun = 1.3927
Thus, Average density of Sun is 1.3927 .
Final velocity = 5km/sec = 5000 m/sec
Initial velocity = 0, mass = 5kg and force = 500,000 N
F = m(Vf-Vi)/time
Time = m(Vf-Vi)/force = 5*5000/500000 = 0.05 seconds
So, it takes 0.05 sec to arrive at the speed of 5km/s.
