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liberstina [14]
2 years ago
8

A motorcycle has a constant speed of 29.6 m/s as it passes over the top of a hill whose radius of curvature is 183 m. The mass o

f the motorcycle and driver is 329 kg. Find the magnitude of (a) the centripetal force and (b) the normal force that acts on the cycle.
Physics
1 answer:
coldgirl [10]2 years ago
8 0

Answer:

a) centripetal force = m v^2 / R = 329 * (29.6 m/s)^2 / 183

F = 1580 Newtons

b) normal force = gravitational force - F = 329 * 9.8 - 1580 = 1640 N

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Force applied = F = 628 N 
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<span>Newton's 2nd law of motion : F = Ma </span>
<span> a = F/M -------- (1) </span>
<span>New mass of the crate = M1 = 3.8M kg </span>
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Answer:1.375metre per second square

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3 years ago
A car traveling at 15 m/s starts to decelerate steadily. It comes to a complete stop in 10 seconds. What is it’s acceleration
tresset_1 [31]

So the initial velocity is 15 m/s, the final velocity is 0 since it's at a complete stop and time is 10 seconds.  Therefore:

Acceleration=\frac{v_{final}-v_{initial}}{t_{final}-t_{initial}} =\frac{0m/s-15m/s}{10s-0s} =-1.5\frac{m}{s^2}

Therefore, the acceleration is -1.5 m/s^2.  The reason it's negative is due to the fact that the vector is going against it's original movement since it's decelerating.

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A large organism is made up of many millions of what
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Answer:

Cells.

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3 0
4 years ago
You attach a meter stick to an oak tree, such that the top of the meter stick is 2.07 meters above the ground. Later, an acorn f
ra1l [238]

Answer:

5.05 m

Explanation:

length of stick (L) = 1 m

distance from the top of the stick to the ground (d) = 2.07 m

time taken for corn to travel the length of the stick (t) = 0.121 s

acceleration due to gravity (a) = 9.8 m/s^{2}

we can get the distance in four stages.

  • Finding the velocity the corn was moving at from s=vt+0.5at^{2}

       where s = length of stick, t = time, a = acceleration due to gravity

       s=vt+0.5at^{2}

       1 = 0.121u + (0.5 x 9.8 x 0.121 x 0.121)

       1 = 0.121v +  0.0717

       1 - 0.0717 = 0.121v

       v = 7.67 m/s

  • Using the velocity above to find the time it took for the corn to fall to the top of the stick from the formula v = u + at' where:

       v = final velocity = 7.67 m/s

       u = initial velocity = 0 m/s since it was initially at rest

       a = acceleration due to gravity

       t' = time taken to fall to the top of the stick

        7.67 = 0 + (9.8 x t')

        t' = 7.67 / 9.8 = 0.78 s

  • using the time above to find the distance between the branch the corn falls from and the top of the stick using s=vt+0.5at^{2} where:

        s = distance

        v = initial velocity = 0 m/s since it was initially at rest

        t = time = 0.78 s

        a = acceleration due to gravity = 9.8

        s = 0 + (0.5 x 9.8 x 0.78 x 0.78)

        s = 2.98 m

  • Add the distance between the branch the corn falls from and the top of the stick and the distance from the top of the stick to the ground.

        2.98 + 2.07 = 5.05 m

       

5 0
3 years ago
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