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liberstina [14]
2 years ago
8

A motorcycle has a constant speed of 29.6 m/s as it passes over the top of a hill whose radius of curvature is 183 m. The mass o

f the motorcycle and driver is 329 kg. Find the magnitude of (a) the centripetal force and (b) the normal force that acts on the cycle.
Physics
1 answer:
coldgirl [10]2 years ago
8 0

Answer:

a) centripetal force = m v^2 / R = 329 * (29.6 m/s)^2 / 183

F = 1580 Newtons

b) normal force = gravitational force - F = 329 * 9.8 - 1580 = 1640 N

You might be interested in
A negative test charge will accelerate toward regions of ________ electric potential and ________ electric potential energy.
dalvyx [7]

Answer: higher and lower

Explanation:

 charge in an electric field will experience a force in the direction of decreasing potential energy. Since the electric potential energy of a negative charge is equal to the charge times the electric potential the direction of decreasing electric potential energy is the direction of increasing electric potential.

5 0
3 years ago
Assume that the Deschutes River has straight and parallel banks and that the current is 0.75 m/s. Drifting down the river, you f
DedPeter [7]

Answer:

    d = 142.5 m

Explanation:

This is a vector exercise. Let's calculate how much the boat travels in the 40s

     d₀ = v_{b} t

    d₀ = 0.75 40

    d₀ = 30 m

Let's write the kinematic equations

Boat

     x = d₀  +  v_{b} t

     x = 0 +  v_{h} t

At the meeting point the coordinate is the same for both

    d₀  +  v_{b} t =  v_{h} t

    t ( v_{h} -  v_{b}) = d₀  

    t = d₀  / ( v_{b}-  v_{h})

The two go in the same direction therefore the speeds have the same sign

     t = 30 / (0.95-0.775)

     t = 150 s

The distance traveled by man is

     d =  v_{h} t

     d = 0.95 150

     d = 142.5 m

3 0
3 years ago
Precipitation tends to be _______ on the _______ side of a mountain because water vapor _______ as it rises there.
Lera25 [3.4K]

Answer:

Higher, Windward side, Condenses

Explanation:

The Windward side refers to that side of a mountain that faces the direction from which the wind is blowing. In this direction, the moisture containing hot air blowing from a distant place moves upward and strikes the mountain at a greater height, where the air mass is thin and the temperature is relatively cold. As the temperature and pressure decrease with altitude, the hot uprising air cools and gradually condenses. This results in the occurrence of high precipitation over this region i.e. the windward side of the mountain.

Therefore, the precipitation is always higher on the windward side of a mountain as the hot air undergoes condensation at greater height as it rises upward.

6 0
3 years ago
Owen throws a baseball straight upward. We can ignore air resistance.
dusya [7]

Answer:

The acceleration of the ball is constant and equal to -9.81 m/s² (acting downwards)

The velocity of the ball reduces at a constant rate with time on its way up

Explanation:

The motion of the ball upwards is described by the following equation;

v = u - g × t

v² = u² - 2 × g × s

Where;

v = The final velocity of the ball

u = The initial velocity of the ball

g = The acceleration due to gravity = Constant

s = The height of the bass after a given time, t

t = The time in which the ball is rising

Therefore, the acceleration of the ball = The acceleration due to gravity  (Constant) = -9.81 m/s²↓

From v = u - g × t = u - 9.81 × t , the velocity of the ball reduces at a constant rate with time on its way up.

7 0
3 years ago
A simple pendulum consisting of a small object of mass m attached to a string of length l has a period T.
andrew-mc [135]

Answer:

Check Explanation.

Explanation:

For a simple pendulum, the period is given as

T = 2π√(L/g)

It is also given as

T = 2π√(m/k)

where

T = period of oscillation

m = mass of the pendulum

L = length

g = acceleration due to gravity

k = force constant

Equating this two equations,

2π√(L/g) = 2π√(m/k)

(L/g) = (m/k)

(m/L) = (k/g)

So, any pendulum that will have the same period as our pendulum with mass, m, and length, L, must have the ratio of (L/g) to be the same as the pendulum under consideration and the ratio of its mass to force constant (m/k) must also be equal to this ratio.

Hope this Helps!!!

4 0
3 years ago
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