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ahrayia [7]
2 years ago
14

ehicle collisions involve huge amounts of energy. How does the crashworthiness of a car affect the transfer and transformations

of the energy and, ultimately, protect the occupants with consideration of the Law of Conservation of Energy.
Physics
1 answer:
Angelina_Jolie [31]2 years ago
8 0

When the two-vehicle collides transformation of the energy is done in terms of kinetic energy.

<h3>What is the law of conservation of energy?</h3>

According to the Law of Conservation of Energy, energy can neither be created nor destroyed, but it can be transferred from one form to another.

The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.

In the above problem, the Vehicle get collides so that the kinetic energy of the vehicle is converted into the kinetic energy of another vehicle the speed of the vehicle will reduce when they collide.

Momentum also gets conserved when the two vehicles collide.

Hence, the transformation of the energy is done in terms of kinetic energy.

To learn more about the law of conservation of energy, refer to brainly.com/question/2137260.

#SPJ1

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3 years ago
Consider a block of mass m attached to two springs, one on the left with spring constant k1 and one on the right with spring con
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T= 2\pi\times sqrt(m/(k1+k2))

Explanation:

When the block is displaced by x units

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Writing Newtons second law, F = ma

-k_1x - k_2x =ma

-k_1x - k_2x = mx''

a= x" ( differentiating x w.r.t time twice)

x''+(k_1/m + k_2/m) x=0

this the standard form of equation of oscillation spring mass system

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since,  Period T=2\pi\sqrt{\frac{m}{K_{eq.}} }

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3 0
3 years ago
A machine part has the shape of a solid uniform sphere of mass 250 g and a diameter of 4.30 cm. It is spinning about a frictionl
zysi [14]

Answer:\alpha =9.302\ rad/s^2

Explanation:

Given

mass of sphere m=250\ gm

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radius r=\frac{4.30}{2}\ cm

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friction will provide resisting torque so

f\times r=I\times \alpha

where I=\text{moment of Inertia}

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0.02\times r=\frac{2}{5}mr^2\times \alpha

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t=\dfrac{\Delta \omega }{\alpha }

t=\dfrac{21}{9.302}

t=2.25\ s

6 0
3 years ago
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