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guajiro [1.7K]
2 years ago
15

Discuss the microstructural transformation of eutectic reaction , hypo eutectic and hyper eutectic. Include temperature, reactio

ns, phase development and phase diagrams
Chemistry
1 answer:
Ket [755]2 years ago
7 0

The phase development of the eutectic reaction includes the equilibrium point of Liquid, crystals of A, and crystals of B

<h3>What is the Eutectic Reaction?</h3>

This refers to the three-phase reaction that occurs when a liquid forms after cooling.

Hence, we can see that the hypo eutectic reaction occurs when there is a homogenous mixture of substances that undergoes a reaction where it melts and solidifies.

The hyper eutectic reaction has to do with the metallic alloy that contains a composition that has exceeded its eutectic point.

Read more about eutectic reactions here:

brainly.com/question/23160517

#SPJ1

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2HgO—&gt;2Hg+O2. I start with 46.8 g HgO. What is my theoretical yield of O2?
jok3333 [9.3K]

Answer:

Theoretical yield = 3.52 g

Percent yield =65.34%

Explanation:

Given data:

Mass of HgO = 46.8 g

Theoretical yield of O₂ = ?

Percent yield of O₂ = ?

Actual yield of O₂ =  2.30 g

Solution:

Chemical equation:

2HgO  →   2Hg + O₂

Number of moles of HgO = mass/ molar mass

Number of moles of HgO = 46.8 g / 216.6 g/mol

Number of moles of HgO = 0.22 mol

Now we will compare the moles of HgO with oxygen.

                         HgO             :             O₂

                             2               :               1

                            0.22           :          1/2×0.22 = 0.11 mol

Theoretical yield:

Mass of oxygen = number of moles × molar mass

Mass of oxygen =  0.11 mol × 32 g/mol

Mass of oxygen = 3.52 g

Percent yield :

Percent yield = actual yield / theoretical yield × 100

Percent yield = 2.30 g/ 3.52 g × 100

Percent yield =65.34%

5 0
3 years ago
I need help with this please help!
inn [45]

Answer: the answer is think it yourself

Explanation:

7 0
3 years ago
Read 2 more answers
How many molecules are in 165 g of carbon dioxide?
Svet_ta [14]
М(СО₂)=165 г

н(СО₂)=м(углекислого газа)/М(СО₂)

Н=Nₐ*м(углекислого газа)/М(СО₂)

Н=6.022*1023 * 165/44.01=2.258*10²⁴
6 0
3 years ago
Read 2 more answers
A galvanic cell at a temperature of 42 degrees Celcius is powered by the following redox reaction:
seropon [69]

<u>Answer:</u> The cell voltage of the given reaction is 1.86 V

<u>Explanation:</u>

The given chemical equation follows:

3Cu^{2+}(aq.)+2Al\rightarrow 2Al^{3+}(aq.)+2Au(s)

<u>Oxidation half reaction:</u> Al(aq.)\rightarrow Al^{3+}(aq.)+3e^-;E^o_{Al^{3+}/Al}=1.66V       ( × 2)

<u>Reduction half reaction:</u> Cu^{2+}(aq.)+2e^-\rightarrow Cu(s);E^o_{Cu^{2+}/Cu}=0.16V       ( × 3)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.16-(-1.66)=1.82V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Al^{3+}]^2}{[Cu^{2+}]^3}

where,

E_{cell} = electrode potential of the cell = ? V

E^o_{cell} = standard electrode potential of the cell = +1.82 V

n = number of electrons exchanged = 2

R = Gas constant = 8.314 J/mol Kl

T = temperature = 42^oC=[42+273]K=315K

F = Faraday's constant = 96500

[Al^{3+}]=1.63M

[Cu^{2+}]=3.43M

Putting values in above equation, we get:

E_{cell}=1.82-\frac{2.303\times 8.314\times 315}{2\times 96500}\times \log(\frac{(1.63)^2}{(3.43)^3})\\\\E_{cell}=1.86V

Hence, the cell voltage of the given reaction is 1.86 V

4 0
3 years ago
What happens when cells are exposed to radioactivity?
Step2247 [10]

Answer:

when cell is exposed to radiation we get brain tumour or cancer.

6 0
3 years ago
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